Question

1. A researcher asked 15 samples of size (n=100) about their social media use. Here are the mean (M) reported number of social media checks per hour for each sample:

Sampling Distribution Homework

5 6 8 10 13 15 20 22 23 25 27 33 39 42 60

What is the best estimate for the population mean (??)? Please give the actual value.

4. Here are the standard deviations for the 15 samples reported in question 3.

1.3 1.5 1.2 2.1 2.0 2.3 2.4 2.1 2.2 2.6 2.5 2.9 2.8 3.1 2.9

What is the best estimate for the population standard deviation (??)?

5. What is the Standard Error of the Mean for the samples of social media checks (use information provided in questions 3 and 4)?

Answer 1

3.

The sample size is n = 15.

The provided sample data along with the data required to compute the sample mean Xˉ and sample variance s^2

	X	X2
	5	25
	6	36
	8	64
	10	100
	13	169
	15	225
	20	400
	22	484
	23	529
	25	625
	27	729
	33	1089
	39	1521
	42	1764
	60	3600
Sum =	348	11360

The sample mean Xˉ is computed as follows:

4.

The sample size is n = 15.

The provided sample data along with the data required to compute the sample mean Xˉ and sample variance s^2

	X	X2
	1.3	1.69
	1.5	2.25
	1.2	1.44
	2.1	4.41
	2.0	4
	2.3	5.29
	2.4	5.76
	2.1	4.41
	2.2	4.84
	2.6	6.76
	2.5	6.25
	2.9	8.41
	2.8	7.84
	3.1	9.61
	2.9	8.41
Sum =	33.9	81.37

The sample mean Xˉ is computed as follows:

5.

Standard Error of the Mean for the samples of social media =

Standard deviation / sqrt ( sample size )

= 2.26 / sqrt (15)

= 2.26 / 3.8729

= 0.5835

Please like