Question
In: Physics
A small bullet of mass m=0.24kg and speed v=17.8m/s embeds in a block of mass M=0.75kg...
A small bullet of mass m=0.24kg and speed v=17.8m/s embeds in a block of mass M=0.75kg suspended by a massless string of length L, after a collision as shown in the figure. If the bullet will appear on the other side of the block M with a speed v'=5m/s, instead of being embedded in it, find the maximum height the block M can reach. (Take g=9.81 m/s2). Express your answer using two decimal places.
Solutions
Expert Solution
Note :- for clear understanding of solution first derived the expression for height
Given data :-
mass of small bullet (m) = 0.24 kg
Mass of a block (M) = 0.75kg
initial speed of bullet (v) = 17.8 m/s
final speed of bullet + block (After embedded) = 5m/s
given g = 9.81 m/s^2
Hence, Maximum height block M can reach h = 0.95 m
genius_generous answered 2 years agoRelated Solutions
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