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A small bullet of mass m=0.24kg and speed v=17.8m/s embeds in a block of mass M=0.75kg...

A small bullet of mass m=0.24kg and speed v=17.8m/s embeds in a block of mass M=0.75kg suspended by a massless string of length L, after a collision as shown in the figure. If the bullet will appear on the other side of the block M with a speed v'=5m/s, instead of being embedded in it, find the maximum height the block M can reach. (Take g=9.81 m/s2). Express your answer using two decimal places.

Solutions

Expert Solution

Note :- for clear understanding of solution first derived the expression for height

Given data :-

mass of small bullet (m) = 0.24 kg

Mass of a block (M) = 0.75kg

initial speed of bullet (v) = 17.8 m/s

final speed of bullet + block (After embedded) = 5m/s

given g = 9.81 m/s^2

Hence, Maximum height block M can reach h = 0.95 m

genius_generous answered 2 years ago
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