Question
In: Physics
A small bullet of mass m=0.24kg and speed v=17.8m/s embeds in a block of mass M=0.75kg...
A small bullet of mass m=0.24kg and speed v=17.8m/s embeds in a block of mass M=0.75kg suspended by a massless string of length L, after a collision as shown in the figure. If the bullet will appear on the other side of the block M with a speed v'=5m/s, instead of being embedded in it, find the maximum height the block M can reach. (Take g=9.81 m/s2). Express your answer using two decimal places.
Solutions
Expert Solution
Note :- for clear understanding of solution first derived the expression for height
Given data :-
mass of small bullet (m) = 0.24 kg
Mass of a block (M) = 0.75kg
initial speed of bullet (v) = 17.8 m/s
final speed of bullet + block (After embedded) = 5m/s
given g = 9.81 m/s^2
Hence, Maximum height block M can reach h = 0.95 m
genius_generous answered 2 years agoRelated Solutions
• If a block of mass m at speed v collides inelastically with a block of...
• If a block of mass m at speed v collides inelastically with a
block of mass M at rest, what is the final velocity of each block?
What fraction of the initial energy is lost?
• Two identical circular hockey pucks of radius r traveling
towards each other at the same speed v collide elastically. Their
centers are separated by a vertical distance d, which is less than
r. After the collision, with what angle relative to the initial...
A bullet of mass 2.0×10−3 kg embeds itself in a wooden block with mass 0.986 kg...
A bullet of mass 2.0×10−3 kg embeds itself in a
wooden block with mass 0.986 kg , which then compresses a spring
(k= 110 N/m ) by a distance 4.0×10−2 mm before coming to
rest. The coefficient of kinetic friction between the block and
table is 0.41.
1) What is the initial speed of the bullet?
2) What fraction of the bullet's initial kinetic energy is
dissipated (in damage to the wooden block, rising temperature,
etc.) in the collision between...
A bullet of mass 2.0×10−3 kgkg embeds itself in a wooden block with mass 0.981 kgkg...
A bullet of mass 2.0×10−3 kgkg embeds itself in a
wooden block with mass 0.981 kgkg , which then compresses a spring
(kkk = 130 N/mN/m ) by a distance 5.5×10−2 mm before
coming to rest. The coefficient of kinetic friction between the
block and table is 0.60.
a. What is the initial speed of the bullet?
b. What fraction of the bullet's initial kinetic energy is
dissipated (in damage to the wooden block, rising temperature,
etc.) in the collision...
A bullet of mass 1.7×10−3 kg embeds itself in a wooden block with mass 0.980 kg...
A bullet of mass 1.7×10−3 kg embeds itself in a wooden block
with mass 0.980 kg , which then compresses a spring (k = 160 N/m )
by a distance 6.0×10−2 m before coming to rest. The coefficient of
kinetic friction between the block and table is 0.53. What is the
initial speed of the bullet?
A block of mass m= 5.00-kg is moving to the right with a speed of v=...
A block of mass m= 5.00-kg is moving to the right with a speed
of v= 2.00 m/son a horizontal,frictionless surface. The block
encounters a relaxed(that is, neither compressed nor
extended)spring with spring constant k= 2,000.00 N/m.
a.What is the kinetic energy of the block before hitting the
spring?
b.What is the kinetic energy of the block when the spring is at
maximum compression?
c.How much energy is stored in the spring at maximum
compression?
d.How far does the spring...
A bullet of mass m = 8.00 g is fired into a block of mass M...
A bullet of mass m = 8.00 g is fired into a block of
mass M = 220 g that is initially at rest at the edge of a
table of height h = 1.00 m (see figure below). The bullet
remains in the block, and after the impact the block lands
d = 2.10 m from the bottom of the table. Determine the
initial speed of the bullet.
___m/s
A bullet of mass m = 8.00 g is fired into a block of mass M...
A bullet of mass m = 8.00 g is fired into a block of
mass M = 210 g that is initially at rest at the edge of a
table of height h = 1.00 m (see figure below). The bullet
remains in the block, and after the impact the block lands
d = 1.90 m from the bottom of the table.
Determine the initial speed of the bullet.
________m/s
A bullet of mass 0.010 kg and speed of 100 m/s is brought to rest in...
A bullet of mass 0.010 kg and speed of 100 m/s is brought to
rest in a wooden block
after penetrating a distance of 0.10 m. The work done on the
bullet by the block is
A.
50 J.
B.
-
50 J.
C.
0.001 J.
D.
-
0.001 J.
E.
zero.
A bullet of mass 148 g and a speed v impacts on a pendulum of mass...
A bullet of mass 148 g and a speed v impacts on a
pendulum of mass 6.18 kg and length 200 cm. The bullet embeds
itself in the pendulum bob. The pendulum then travels in a complete
and perfect circle.
(a) If the pendulum is suspended by a light, stiff rod, what is the
minimum speed of the bullet?
(b) If the pendulum is suspended by a string, what is the minimum
speed of the bullet?
A bullet of mass m = 29 g is fired into a wooden block of mass...
A bullet of mass m = 29 g is fired into a wooden block of mass M
= 4.9 kg as shown in the figure below. The block is attached to a
string of length 1.5 m. The bullet is embedded in the block,
causing the block to then swing as shown in the figure. If the
block reaches a maximum height of h = 0.27 m, what was the initial
speed of the bullet?
ADVERTISEMENT
ADVERTISEMENT
Latest Questions
- Ten-year zero coupon bonds issued by the U.S. Treasury have a face value of $1,000 and...
- The Blossom Department of Transportation has issued 25-year bonds that make semiannual coupon payments at a...
- Please answer all 4 parts of this question John Johnson just received a cash gift from...
- Question #1 C4H10O with a butanol combustion cycle (formation enthalpy-332,000 kJ / kmol) 25 per cent...
- Suppose a survey revealed that 19% of 494 respondents said they had in the past sold...
- Topic: Choose a company which are you are starting, and a main product or service that...
- 4. Why did the United States and the Soviet Union find themselves in a “Cold War”...
ADVERTISEMENT