A bullet of mass 2.0×10−3 kg embeds itself in a wooden block with mass 0.986 kg...

A bullet of mass 2.0×10⁻³ kg embeds itself in a wooden block with mass 0.986 kg , which then compresses a spring (k= 110 N/m ) by a distance 4.0×10⁻² mm before coming to rest. The coefficient of kinetic friction between the block and table is 0.41.

1) What is the initial speed of the bullet?

2) What fraction of the bullet's initial kinetic energy is dissipated (in damage to the wooden block, rising temperature, etc.) in the collision between the bullet and the block?

Expert Solution

In the question the compression distance is given in (mm) which has to be in (m) for proper practical condition and calculations.

genius_generous answered 2 years ago

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