In: Statistics and Probability
Binge Drinking Episodes in Past Month |
|||
0 |
1 |
2+ |
|
9 |
11 |
12 |
N = 15 |
7 |
11 |
14 |
|
11 |
8 |
13 |
G = 165 |
8 |
10 |
16 |
|
10 |
10 |
15 |
ΣX2 = 1911 |
M = 9 |
M = 10 |
M = 14 |
|
T = 45 |
T = 50 |
T = 70 |
|
SS = 10 |
SS = 6 |
SS = 10 |
(a)
We have to test for null hypothesis
against the alternative hypothesis
Our test statistic is given by
Here,
Number of groups
Number of observations in different groups
Total number of observations
(i)
Sample means of different groups are given by
(ii)
Grand mean is given by
(iii)
Between groups mean sum of squares is given by
Within groups mean sum of squares is given by
(iv)
Degrees of freedom
[Using R-code '1-pf(16.15384,2,12)']
(v)
Level of significance
(vi)
We reject our null hypothesis if
Here, we observe that
So, we reject our null hypothesis.
(b)
Hence, based on the given data we can conclude that there are significant differences in perfectionism among persons experiencing 0, 1, or 2+ binge drinking episodes within the last month.