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For the reaction A+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants....

For the reaction A+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants. The following data were collected: Trial [A] (M) [B] (M) [C] (M) Initial rate (M/s) 1 0.20 0.20 0.20 6.0×10−5 2 0.20 0.20 0.60 1.8×10−4 3 0.40 0.20 0.20 2.4×10−4 4 0.40 0.40 0.20 2.4×10−4 Rate law equation The rate of a chemical reaction depends on the concentrations of the reactants. For the general reaction between Aand B, aA+bB⇌cC+dD The dependence of the reaction rate on the concentration of each reactant is given by the equation called the rate law: rate=k[A]m[B]n where k is a proportionality constant called the rate constant. The exponent m determines the reaction order with respect to A, and n determines the reaction order with respect to B. The overall reaction order equals the sum of the exponents (m+n). Part A What is the reaction order with respect to A? Express your answer as an integer. SubmitHintsMy AnswersGive UpReview Part Part B What is the reaction order with respect to B? Express your answer as an integer. SubmitHintsMy AnswersGive UpReview Part Part C What is the reaction order with respect to C? Express your answer as an integer.

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Expert Solution

The table is:

Trial [A] (M) [B] (M) [C] (M) Initial rate (M/s)
1 0.20 0.20 0.20 6.0*10-5
2 0.20 0.20 0.60 1.8*10-4
3 0.40 0.20 0.20 2.4*10-4
4 0.40 0.40 0.20 2.4*10-4

When we see the table and compare the trials, we will get the order with respect to each reactant.

By comparing trials 1 and 2, the concentration of A and B are same, just the concentration of C is thrice of that in trial 1. The initial rate is also thrice. This means that rate is directly proportional to [C].

rate = k [C]

By comparing trials 1 and 3, the concentration of B and C are same, just the concentration of A is twice of that in trial 1. The initial rate is four times. This means that rate is directly proportional to square of [A].

rate = k [A]2

By comparing trials 3 and 4, the concentration of A and C are same, just the concentration of B is twice of that in trial 1. The initial rate is same in both cases. This means that rate does not depend on [B].

rate = k [B]0

The reaction order with respect to A is 2, with respect to B is 0 and with respect to C is 1.

queen_honey_blossom answered 1 year ago
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