Question
In: Chemistry
A reaction was run with two different initial concentrations of reactants A and B: Experiment A...
A reaction was run with two different initial concentrations of reactants A and B:
|
Experiment |
A / M |
B / M |
rateB / (M/sec) |
|
1 |
0.00022 |
0.00046 |
0.0841 |
|
2 |
0.00022 |
0.00166 |
0.3035 |
What is the order of the reaction with respect to B?
A reaction was run with two different initial concentrations of reactants A and B:
|
Experiment |
A / M |
B / M |
rateB / (M/sec) |
|
1 |
0.00057 |
0.00067 |
0.0000825 |
|
2 |
0.00057 |
0.00621 |
0.0657 |
What is the order of the reaction with respect to B?
Solutions
Expert Solution
1)
let r= k*[A]^x [B]^y
put the values from both experiments to get 2 equations
0.0841 = k* (0.00022)^x *
(0.00046)^y
.....eqn 1
0.3035 = k* (0.00022)^x *
(0.00166)^y
.....eqn 2
divide eqn 2 by 1
0.3035/0.0841 = (0.00166/0.00046)^y
3.61 = (3.61)^y
so,y=1
the order of the reaction with respect to B =1
2)
let r= k*[A]^x [B]^y
put the values from both experiments to get 2 equations
0.0000825 = k* (0.00057)^x *
(0.00067)^y
.....eqn 1
0.0657= k* (0.00057)^x *
(0.00621)^y
.....eqn 2
divide eqn 2 by 1
0.0657/0.0000825 = (0.00621/0.00067)^y
796.34 = (9.27)^y
take log on both sides
log (796.34) = y * log (9.27)
y= log (796.34) / log(9.27)
=3
so,y=3
the order of the reaction with respect to B =3
queen_honey_blossom answered 3 years agoRelated Solutions
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[B]
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[C]
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For the reaction A+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants....
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[A]
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[B]
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[C]
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Initial rate
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1
0.10
0.10
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0.30
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following data were collected: Trial [A] (M) [B] (M) [C] (M)
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following data were collected:
Trial
[A][A]
(MM)
[B][B]
(MM)
[C][C]
(MM)
Initial rate
(M/sM/s)
1
0.30
0.30
0.30
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0.30
0.30
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