Question

In: Chemistry

2. A mixture weighing 42.500 g contains 7.500 g NH4Cl, 19.650 g SiO2. With the remainder...

2. A mixture weighing 42.500 g contains 7.500 g NH4Cl, 19.650 g SiO2. With the remainder being NaCl. Find the percent by weight of each component. Show your calculations.

Expert Solution

Solution :-

mass of mixture = 42.500 g

mass of NH4Cl = 7.500 g

mass of SiO2 = 19.650 g

mass of NaCl = mass of mixture - [mass of NH4Cl + mass of SiO2]

= 42.500 g - [7.500 g +19.650 g]

= 15.350 g

now lets find the percent of the each

% NH4Cl =( mass of NH4Cl/mixture mass )*100%

=(7.500g/42.500g)*100%

= 17.647 %

% SiO2 = =( mass of SiO2 /mixture mass )*100%

=(19.650 g / 42.500g)*100%

= 46.235 %

%NaCl = =( mass of NaCl/mixture mass )*100%

=(15.35 g/42.500g)*100%

= 36.117 %

queen_honey_blossom answered 1 year ago

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