In: Chemistry
A gaseous mixture contains 413.0 Torr of H2(g), 391.5 Torr of N2(g), and 65.7 Torr of Ar(g). Calculate the mole fraction, X, of each of these gases.
PH2 =413 Torr
PN2 = 391.5 Torr
PAr = 65.7 Torr
Total pressure = PH2 + PN2 + PAr
= 413+391.5 +65.7 =870.2 Torr
partial pressure = mole fraction of gas* total pressure
PH2 = XH2 * PT
413 = XH2 *870.2
XH2 = 413/870.2 = 0.475
PN2 = XN2 * PT
391.5 = XN2 *870.2
XN2 = 391.5/870.2 = 0.45
PAr = XAr * PT
65.7 = XAr *870.2
XAr = 65.7/870.2 = 0.0755