A mixture contains only and . A 4.51-g sample of the mixture is dissolved in water...

A mixture contains only and . A 4.51-g sample of the mixture is dissolved in water and an excess of is added, producing a precipitate of . The precipitate is filtered, dried, and weighed. The mass of the precipitate is 1.06 g. What is the mass percent of in the sample?

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Expert Solution

mass percent of precipitate in the sample = mass of precipitate / mass of sample *100

= 1.06/4.51*100

= 23.5%

queen_honey_blossom answered 1 year ago

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