In: Chemistry
A mixture of gases contains 8.23 g of N2, 8.80 g of H2, and 6.96 g of NH3. If the total pressure of the mixture is 3.05 atm, what is the partial pressure of each component?
A mixture of gases contains 8.23 g of N2, 8.80 g of H2, and 6.96 g of NH3. If the total
moles of N2 = mass / molar mass = 8.23 / 28
= 0.294
moles of H2 = 8.80 / 2 = 4.40
moles of NH3 = 6.96 / 17 = 0.409
total moles = 0.294 + 4.40 + 0.409 = 5.103
mole fraction of N2 = moles of N2 / total moles = 0.294 / 5.103
= 0.0576
mole fraction of H2 = 4.40 / 5.103 = 0.862
mole fraction of NH3 = 0.409 / 5.103 = 0.080
Partial pressure of N2 = mole fraction of N2 x total pressure
= 0.0576 x 3.05
= 0.176 atm
partial pressure of H2 = mole fraction of H2 x total pressure
= 0.862 x 3.05
= 2.63 atm
partial pressure of NH3 = mole fraction of NH3 x total pressure
= 0.080 x 3.05
= 0.244