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A mixture of gases contains 8.23 g of N2, 8.80 g of H2, and 6.96 g...

A mixture of gases contains 8.23 g of N2, 8.80 g of H2, and 6.96 g of NH3. If the total pressure of the mixture is 3.05 atm, what is the partial pressure of each component?

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Expert Solution

A mixture of gases contains 8.23 g of N2, 8.80 g of H2, and 6.96 g of NH3. If the total

moles of N2 = mass / molar mass = 8.23 / 28

                  = 0.294

moles of H2 = 8.80 / 2 = 4.40

moles of NH3 = 6.96 / 17 = 0.409

total moles = 0.294 + 4.40 + 0.409 = 5.103

mole fraction of N2 = moles of N2 / total moles = 0.294 / 5.103

                                = 0.0576

mole fraction of H2 = 4.40 / 5.103 = 0.862

mole fraction of NH3 = 0.409 / 5.103 = 0.080

Partial pressure of N2 = mole fraction of N2 x total pressure

                                    = 0.0576 x 3.05

                                    = 0.176 atm

partial pressure of H2 = mole fraction of H2 x total pressure

                                   = 0.862 x 3.05

                                   = 2.63 atm

partial pressure of NH3 = mole fraction of NH3 x total pressure

                                      = 0.080 x 3.05

                                      = 0.244

queen_honey_blossom answered 1 month ago
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