Question

In: Biology

1. In an experiment, you grow E. coli cells in the lab at different temperatures. After...

1. In an experiment, you grow E. coli cells in the lab at different temperatures. After the growth, you isolate their cell membranes, perform complete hydrolysis of their cell membranes and isolate and quantify the percentages of different fatty acids in your final sample. How would you expect the fraction of myristic acid to change as you increase the temperature?  

2. Succinyl-CoA is a negative regulator of α-ketoglutarate-dehydrogenase complex. Explain why this makes sense, and propose a possible mechanism for how this molecule inhibits citrate synthase. What other step of the citric acid cycle is inhibited by succinyl- CoA, and how do you expect that inhibition mechanism to be similar/different?

3. In gluconeogenesis, the pyruvate to phosphoenolpyruvate is one of the bypass steps that is different from the reverse reaction in glycolysis due to the irreversible nature of pyruvate kinase. There are two pathways for this bypass reaction that differ in the location where the final PEP product is synthesized – either in the mitochondria or in the cytoplasm. Assume that your cell is undergoing gluconeogenesis using pyruvate derived from the deamination of serine by the enzyme serine dehydratase:

L-serine → Pyruvate + NH3

Which of the two pathways of phosphoenolpyruvate synthesis will be used and why? What are the intermediate steps for this reaction, and where do they occur?

Solutions

Expert Solution

1. The transition temperature is a function of the membrane lipid composition and in organisms deficient in cholesterol, mainly depends on the fatty acid composition of the membrane lipids. Phospholipids that contain unsaturated fatty acids (UFAs) have much lower transition temperatures than those lipids made of saturated fatty acids (SFAs).  The E. coli cells have mechanisms to change the relative amounts of saturated fats and unsaturated fats in their cell membranes. The higher the cell's growth temperature, the less unsaturated material; the lower the temperature the more unsaturated material. This turns out to be essential for survival. Myristic acid is a 14-carbon, unsaturated fatty acid. Therefore higher the temperature of E. coli cell's growth less the fraction of myristic acid.

2. Succinyl-CoA is a negative regulator of α-ketoglutarate-dehydrogenase complex. Several allosteric inhibitors such as NADH and ATP (both of which are products of the Citric acid cycle) that control the activity of citrate synthase. These two molecules bind allosterically to citrate synthase and decrease its affinity for it substrates. Succinyl-coA is a product of a later step in the Citric acid cycle and it accumulation in the mitochondrial matrix indicates an abundance of electron carriers (in the form of NADH and FADH2) and hence free energy (in the form of ATP) in the cell, suggesting that catabolism can be halted. Succinyl-coA, regulates citrate synthase through competitive inhibition by binding to its active site, thus blocking access of the substrate to the binding site. Thus, succinyl-coA serves as a competitive feedback inhibitor of citrate synthase by inhibiting over catalysis of the citric acid cycle and stopping further catabolism.

3. The majority of the enzymes responsible for gluconeogenesis are found in the cytoplasm. A few exceptions are mitochondrial pyruvate carboxylase and phosphoenolpyrvate carboxykinase (animals).

Synthesis of serine

The intermediates in the pathways of gluconeogenesis are involved in the synthesis of serine, either from glucose via glycolysis or from the triose phosphate pool, where carbon is generated from citric acid cycle intermediates.


Related Solutions

1. Lab Review: A) Explain why– control E. coli cells cannot grow on LBA+amp and LBA+amp+X-Gal....
1. Lab Review: A) Explain why– control E. coli cells cannot grow on LBA+amp and LBA+amp+X-Gal. B) Name a procedure which can replace the heat shock process and achieve the same goal: C) If you used the pBLU plasmid as a vector to carry a desirable human gene into E. coli recipient cells. The insertion site is inside the β-galactosidase gene on the p-BLU plasmid. After the transformation, you plate the cells on LBA+amp+X-Gal to screen for E. coli cells...
1. What would happen if you tried to look at the E. coli cells under the...
1. What would happen if you tried to look at the E. coli cells under the microscope immediately after the decolorizing step?
You found five T4 rII- mutants that will not grow on E. coli K. You mixed...
You found five T4 rII- mutants that will not grow on E. coli K. You mixed together all possible combinations of the two mutants (as indicated in the following chart), added the mixtures to E. coli K and scored for the ability of the mixtures to grow and make plaques (indicated as a + in the chart). 1 2 3 4 5 1 - + + - + 2 - - + - 3 - + - 4 - +...
1. Which organism is easier to grow in the laboratory, E. coli, or Neisseriae gonorrhea? 2....
1. Which organism is easier to grow in the laboratory, E. coli, or Neisseriae gonorrhea? 2. Describe the growth of E. coli in (on) soft agar.
Wild-type E. coli can grow on minimal medium. You have isolated a mutant strain of E....
Wild-type E. coli can grow on minimal medium. You have isolated a mutant strain of E. coli that grows poorly in minimal medium that contains lactose and arabinose and lacks glucose. In ONPG-containing minimal medium lacking glucose the mutant strain produces very low levels of b-galactosidase activity in both the absence and presence of IPTG. The strain does not grow well when transformed with a plasmid containing the lacZ and lacY genes. The strain also does not grow well when...
1. The mixed culture in an experiment was prepared by mixing overnight E. coli and S....
1. The mixed culture in an experiment was prepared by mixing overnight E. coli and S. aureus cultures in the ratio 2:8. However, there seemed to be more E. coli growth on the resulting streak plate than S. aureus growth. Explain this.   2. It was observed that some colonies of the same bacterial species appeared in different sizes on the streak plates. Give the possible reason for this. 3. Is it better to prepare pure culture in broth or on...
Demo Problem You are planning a mapping experiment to map several genes in E. coli. You...
Demo Problem You are planning a mapping experiment to map several genes in E. coli. You choose the following strains of E. coli: lac+, gal+, trp+, his+, strS          X        lac-, gal-, trp-, his- strR Trp refers to the amino acid tryptophan and his refers to the amino acid histidine; str refers to the antibiotic streptomycin with S indicating sensitivity and R indicating resistance. Lac and gal refer to the sugars lactose and galactose (glucose is the default carbon source). To...
. You have extracted extrachromosomal DNA and genomic DNA from E. coli in the lab. What...
. You have extracted extrachromosomal DNA and genomic DNA from E. coli in the lab. What is the differentiating steps during the DNA isolation so that your target DNA is not contaminated with the other unwanted DNA (i.e. you are targeting extrachromosomal DNA, so you don’t want the genomic DNA, and vice-versa)? Why and how that step can differentiate between these groups of DNA
Consider a colony of E. coli cells in which the gene for the CRP protein is...
Consider a colony of E. coli cells in which the gene for the CRP protein is deleted. Describe the effect of that this deletion will have on the arabinose operon in terms of levels of Ara A protein (one of the proteins encoded by a gene in the ara operon) when the cells are grown in media containing arabinose but no glucose. Explain your reasoning.
PREPARATION OF COMPETENT CELLS and TRANSFORMATION: 2a. We will be preparing competent MM294 (E. coli) cells...
PREPARATION OF COMPETENT CELLS and TRANSFORMATION: 2a. We will be preparing competent MM294 (E. coli) cells using a chemical treatment of CaCl2. What are MM294 cells, why do we use them? Define “competent” cells and describe why/how CaCl2 makes cells “competent”. Why is “mid-log” phase important? Support your drawing with a cartoon of what cells “look like” before and after treatment. 2b. What does “heat-shock” do (in the transformation procedure)? 2c. What is LB? What does “LB” stand for and...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT