Question

In: Biology

1. The mixed culture in an experiment was prepared by mixing overnight E. coli and S....

1. The mixed culture in an experiment was prepared by mixing overnight E. coli and S. aureus cultures in the ratio 2:8. However, there seemed to be more E. coli growth on the resulting streak plate than S. aureus growth. Explain this.  

2. It was observed that some colonies of the same bacterial species appeared in different sizes on the streak plates. Give the possible reason for this.

3. Is it better to prepare pure culture in broth or on agar plate? Explain.                  

Solutions

Expert Solution

1. The mixed culture in an experiment was prepared by mixing overnight E. coli and S. aureus cultures in the ratio 2:8. However, there seemed to be more E. coli growth on the resulting streak plate than S. aureus growth. The reason for the above observation is becuase of the difference of doubling time of E.Coli and S.aureus. Doubling time refers to the amount of time required by a cell to double in its number under a constant growth rate. The doubling time of E.Coli is 20 minutes wheras that of S.aureus is in the range of 2 to 4 hours. Now this explains very well that although the amount of inoculum used for S.aureus was more still the growth rate of the same was less because of extended doubling time.

2. It was observed that some colonies of the same bacterial species appeared in different sizes on the streak plates. This phenomenon is possible because of different growth rate of bacteria. Some cells of the same bacterial population would be lag or log or stationary phase. Cells present in different stages will give different colony sizes on the streak plates.

3. It is always better to prepare pure culture in agar plate as compared to broth culture. A pure culture contains only one single type of that organism and therefore it is referred to pure culture. On an agar plate, we can streak the bacterial culture available and then we can observe all colonial morphology. A pure culture would always give rise to same colony which is going to have all features same. On the otherhand Broth cultures are liquid cultures which are used to grow bacteria in a sterile growth medium. So when a culture is inoculated, we wont be able to see the indiviual colonies as all the bacterial cells are going to grow in liquid culture showing turbidity. Hence a pure culture should be grown in agar plate and not in broth culture so that morphologically we will be able to visualize the pure colonies on the agar plate which is difficult in broth culture.


Related Solutions

1. In an experiment, you grow E. coli cells in the lab at different temperatures. After...
1. In an experiment, you grow E. coli cells in the lab at different temperatures. After the growth, you isolate their cell membranes, perform complete hydrolysis of their cell membranes and isolate and quantify the percentages of different fatty acids in your final sample. How would you expect the fraction of myristic acid to change as you increase the temperature?   2. Succinyl-CoA is a negative regulator of α-ketoglutarate-dehydrogenase complex. Explain why this makes sense, and propose a possible mechanism for...
A grad student has a culture of E. coli with a total volume of 600 mL,...
A grad student has a culture of E. coli with a total volume of 600 mL, and OD reading at 550 nm of 1.7. He makes serial dilutions of the culture, starting with a transfer of 1 mL culture into 9 mL tryptone broth. Next, he transfers 0.1 mL of this dilution into 0.9 mL tryptone broth, and repeats this two more times to make a total of 4 serial dilutions. He then pipets 200 uL from the fourth dilution...
In an experiment, E. Coli that are auxotrophic for methionine, tryptophan, and adenine biosynthesis are grown...
In an experiment, E. Coli that are auxotrophic for methionine, tryptophan, and adenine biosynthesis are grown on petri dishes containing rich media with all of these nutrients. The bacteria grow into normal colonies. The same bacteria are plated onto media that is lacking those 3 nutrients (minimal media) and no growth is observed. A second strain of E. Coli which is auxotrophic for histodine, and leucine is also able to grow on rich media but not minimal media. After mixing...
You have an E. coli culture of which you are trying to determine the cell concentration....
You have an E. coli culture of which you are trying to determine the cell concentration. You need to perform a serial dilution. You take 100 µL of the undiluted stock culture, add it to 9.9 mL water in tube A, and mix. Then you take 100 µL of the material in tube A, add it to 9.9 mL water in tube B, and mix. Then you take 100 µL of the material in tube B, add it to 9.9...
You found five T4 rII- mutants that will not grow on E. coli K. You mixed...
You found five T4 rII- mutants that will not grow on E. coli K. You mixed together all possible combinations of the two mutants (as indicated in the following chart), added the mixtures to E. coli K and scored for the ability of the mixtures to grow and make plaques (indicated as a + in the chart). 1 2 3 4 5 1 - + + - + 2 - - + - 3 - + - 4 - +...
Transcribe the following sentences "HEART: regular rate and rhythm." "Stool culture was positive for E. coli."...
Transcribe the following sentences "HEART: regular rate and rhythm." "Stool culture was positive for E. coli." "Lungs: clear to auscultation and percussion."
·       In one experiment Lederberg used Gal+ and Gal– strains of E. coli. One half of...
·       In one experiment Lederberg used Gal+ and Gal– strains of E. coli. One half of a plate that contained medium with galactose as the only carbon source was inoculated with phages that came from lysed cells of the Gal+ strain. The other half of the plate was left uninoculated. A Gal- strain was then placed on the entire plate. Numerous colonies appeared on the half of the plate inoculated with the phage, whereas only a few appeared on the...
You have just synthesized a new antibiotic effective at preventing E. coli growth in agar culture....
You have just synthesized a new antibiotic effective at preventing E. coli growth in agar culture. Now speculate on the proposed mechanism for the newly synthesized antibiotic’s interaction with ATCase. Describe the two limiting possible mechanisms by indicating the involvement of specific subunits of ATCase: 1. Competitive inhibitor 2. Allosteric effector
Suppose that you carried out a Bacterial transformation of E. coli HA101 with pGLO plasmid experiment...
Suppose that you carried out a Bacterial transformation of E. coli HA101 with pGLO plasmid experiment in the lab. During the experiment, plates with bacteria were inoculated from +GLO and -GLO microfuge tubes (LB (-) plate, LB/amp (-) plate, LB/amp (+) plate, and LB/amp/ara (+) plate).             5) What does LB (-) plate contain? 6) What does LB/ amp (-) plate contain? 7) What does LB/amp (+) plate contain? 8) What does LB/amp/ara (+) plate contain?
Demo Problem You are planning a mapping experiment to map several genes in E. coli. You...
Demo Problem You are planning a mapping experiment to map several genes in E. coli. You choose the following strains of E. coli: lac+, gal+, trp+, his+, strS          X        lac-, gal-, trp-, his- strR Trp refers to the amino acid tryptophan and his refers to the amino acid histidine; str refers to the antibiotic streptomycin with S indicating sensitivity and R indicating resistance. Lac and gal refer to the sugars lactose and galactose (glucose is the default carbon source). To...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT