solve: y''+8y'+7'=f(t), y(0)=y'(0)=0, expressing your answer in terms of a convolution, using partial fractions for: i)f(t)=e^t...

solve: y''+8y'+7'=f(t), y(0)=y'(0)=0, expressing your answer in terms of a convolution, using partial fractions for:

i)f(t)=e^t

ii)f(t)=t^1/2

iii) f(t)=2sin(2t)

Expert Solution

Colby Messinger answered 2 years ago

solve: y''+8y'+7y=f(t), y(0)=y'(0)=0, expressing your answer in terms of a convolution, using partial fractions for: i)f(t)=e^t...

solve: y''+8y'+7y=f(t), y(0)=y'(0)=0, expressing your answer in terms of a convolution, using partial fractions for: i)f(t)=e^t ii)f(t)=t^1/2 iii) f(t)=2sin(2t)

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Solve the differential equation. y'' − 8y' + 20y = te^t, y(0) = 0, y'(0) = 0 (Answer using fractions)

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