Solve: y'''−7y''+8y'+16y=0 y(0)=1, y'(0)=−3, y''(0)=10y(0)=1, y′(0)=-3, y′′(0)=10 y(t)= ?

Solve:

y'''−7y''+8y'+16y=0

y(0)=1, y'(0)=−3, y''(0)=10y(0)=1, y′(0)=-3, y′′(0)=10

y(t)= ?

Expert Solution

Colby Messinger answered 7 months ago

solve: y''+8y'+7y=f(t), y(0)=y'(0)=0, expressing your answer in terms of a convolution, using partial fractions for: i)f(t)=e^t...

solve: y''+8y'+7y=f(t), y(0)=y'(0)=0, expressing your answer in terms of a convolution, using partial fractions for: i)f(t)=e^t ii)f(t)=t^1/2 iii) f(t)=2sin(2t)

Solve the differential equation. y'' − 8y' + 20y = te^t, y(0) = 0, y'(0) =...

Solve the differential equation. y'' − 8y' + 20y = te^t, y(0) = 0, y'(0) = 0 (Answer using fractions)

solve for the second order initial value problem= y"-6y+8y=0 y(0)=3, y'(0)=10

solve this equation y''-6y'+8y=1 when y(0)=1, y'(0)=7

Solve the equation y'=5-8y with initial condition y'(0)=0

Solve x′=x−8y, y′=x−3y, x(0)=2, y(0)=1

solve: y''+8y'+7'=f(t), y(0)=y'(0)=0, expressing your answer in terms of a convolution, using partial fractions for: i)f(t)=e^t...

solve: y''+8y'+7'=f(t), y(0)=y'(0)=0, expressing your answer in terms of a convolution, using partial fractions for: i)f(t)=e^t ii)f(t)=t^1/2 iii) f(t)=2sin(2t)

Solve the equation below for y(t): y''+2y'-3y=8u(t-3): y(0) = 0; y'(0)=0

Solve the following differential equation: y''+4y'+4y=u(t-1)-u(t-3), y(0)=0, y'(0)=0

3 Solve the following IVP a) y"+8y'-9y=0 y(1)=1, y'(1)=0 b)y"+4y'+5y=0 y(0)=1, y'(0)=0 c) y"-6y'+9y=0 y(0)=0, y'(0)=2...

3 Solve the following IVP a) y"+8y'-9y=0 y(1)=1, y'(1)=0 b)y"+4y'+5y=0 y(0)=1, y'(0)=0 c) y"-6y'+9y=0 y(0)=0, y'(0)=2 d)y"+4y'+4y=0 y(-1)=2, y'(-1)=1

Question