In: Statistics and Probability
50 percent of all persons in the U.S. population have at least some college education. Choose 10 persons at random. Find the probability of the following. Hint: Use the binom.dist function or the table starting on page 770. Exactly 5 have some college education. At most 5 have some college education.
We can solve this problem with the help of Excel:
We are given with n = 10 person and probability of success, p = 50% = 0.50
Go to Megastat>Probability.
Then go to Discrete Probability Distribution, and it will move on to the binomial distribution.
Select n = 10 and p = 0.50 and press OK.
The output generated is as follows:
10 | n | |||
0.5 | p | |||
cumulative | ||||
X | P(X) | probability | ||
0 | 0.00098 | 0.00098 | ||
1 | 0.00977 | 0.01074 | ||
2 | 0.04395 | 0.05469 | ||
3 | 0.11719 | 0.17188 | ||
4 | 0.20508 | 0.37695 | ||
5 | 0.24609 | 0.62305 | ||
6 | 0.20508 | 0.82813 | ||
7 | 0.11719 | 0.94531 | ||
8 | 0.04395 | 0.98926 | ||
9 | 0.00977 | 0.99902 | ||
10 | 0.00098 | 1.00000 | ||
1.00000 | ||||
5.000 | expected value | |||
2.500 | variance | |||
1.581 | standard deviation |
The bar chart for the data is:
Find the probability of the following:
(a) Exactly 5 have some college education.
From the output, the probability of exactly 5 have some college education is 0.24609.
(b) At most 5 have some college education.
Probability( At most 5 have some college education) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)
= 0.00098 + 0.00977 + 0.04395 + 0.11719 + 0.20508 + 0.24609
= 0.62305