In: Operations Management
A job in an insurance office involves telephone conversations
with policyholders. The office manager estimates that about half of
the employee’s time is spent on the telephone. How many
observations are needed in a work sampling study to estimate that
time percentage to within 4 percent and have a confidence of 95.5
percent? (Round z values to 2 decimal places. Do not round
other intermediate calculations. Round your final answer to the
nearest whole number.)
Number of observations
Z = number of standard deviations need.
= Sample proportion = 0.5 since half of the employees is mentioned
n = sample size
z value for 95.5/2 or 47.75 is 2.01
n = (2.01/0.04)2 * 0.5 (1-0.5)
n = 631.265625
n = 631 observations