Question

In: Statistics and Probability

5) After implementing a new strategy to improve services for patients, the Emergency Department of a...

5) After implementing a new strategy to improve services for patients, the Emergency Department of a hospital claims customers spend fewer than 20 minutes on average to see a physician. A randomly selected sample of 132 patients shows the average wait time of 18.2 minutes. Test the Emergency Department's claim at the 10% level of significance, assuming the standard deviation of wait time for all patients in that hospital is 2.3 minutes

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Answer:-

Given That:-

5) After implementing a new strategy to improve services for patients, the Emergency Department of a hospital claims customers spend fewer than 20 minutes on average to see a physician. A randomly selected sample of 132 patients shows the average wait time of 18.2 minutes. Test the Emergency Department's claim at the 10% level of significance, assuming the standard deviation of wait time for all patients in that hospital is 2.3 minutes

Here, we have to use one sample z test for the population mean.

The null and alternative hypotheses are given as below:

Null hypothesis: : Customers spend 20 minutes on average to see a physician.

Alternative hypothesis: : Customers spend fewer than 20 minutes on average to see a physician.

versus

This is a lower tailed test.

The test statistic formula is given as below:

From given data, we have

Critical value

(by using z-table or excel)

Z = -8.9915

P-value = 0.0000

(by using Z-table)

P-value

So, we reject the null hypothesis

There is sufficient evidence to conclude that Customers spend fewer than 20 minutes on average to see a physician.


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