In: Statistics and Probability
A. Identify a topic of interest to estimate the mean of a population that you would like to set up a confidence interval for: (example – mean weight of the players on the Chicago Bears): Mean weight of the Dallas Cowboys football players.
B. Identify the population you are trying to study.: Dallas Cowboys football players
C. Collect at least 30 sample values from your population for your topic and list the results below. Instead of conducting a “scientific” survey using sound principles of random selection, use a convenience sample consisting of respondents or data that is readily available from your population.
Bradlee Anae
257
Darius Anderson
195
Dorance Armstrong
255
Chidobe Awuzie
202
Blake Bell
252
Francis Bernard
230
Tyler Biadasz
316
Anthony Brown
196
Noah Brown
225
Ventell Bryant
205
Deante Burton
205
Maurice Canady
193
Ron'Dell Carter
269
Jordan Chunn
230
Ha Ha Clinton-Dix
211
La'el Collins
320
Amari Cooper
210
Tyrone Crawford
290
Andy Dalton
220
Trevon Diggs
195
Ben DiNucci
209
Rico Dowdle
215
Ezekiel Elliott
228
Kai Forbath
197
Neville Gallimore
302
Michael Gallup
198
Luke Gifford
243
C.J. Goodwin
190
Stephen Guidry
200
Chris Jones
205
D. Use technology (Excel, statistical calculator website or graphing calculator) to compute the sample mean and sample standard deviation and list them below.
E. Construct a 95% confidence interval for the mean of your sample. (Be sure to use the formulas from section 7.2)
F. Identify the shortcomings of using a convenience sample, and try to identify how a sample of subjects randomly selected form the population might be different.
D) Here, we have to use technology (Excel, statistical calculator website or graphing calculator) to compute the sample mean and sample standard deviation and list them below.
Steps to perform the mean and standard deviation in excel is-
1. Enter the values in a single column.
2. Select the data and click on formula tab.
3. Select the mean and standard deviation formula from statistical option and enter the range of the column here A1 to A30.
4. Click OK.
After running the above steps we get,
mean = 228.77
standard deviation = 37.86
E) Here we have to construct a 95% confidence interval for the mean of your sample.
Formula:
which is obtained from t-distribution table.
So, (228.77-37.86*2.045/5.477,228.77+37.86*2.045/5.477)
= (214.63,242.90)
F) Let us consider the hypothesis,
H0: µ = 0 vs H1: µ ≠ 0
The test statistic used is –
where, n is the sample number = 30
µ0 is the population mean = 0
s is the sample standard deviation
is the sample mean
where, = 228.77
= 37.86
Therefore, T = 5.477(228.77-0)/37.86 = 33.1
The critical value is
which is obtained from t-distribution table.
Now we reject the null if |T| > 2.045. So here, |T|>2.045 so we reject the null and conclude that, the sample of subject randomly selected are not different from the population.