A 500-mL flask of Ne at 500 torr is connect ed to a 300 mL flask...

A 500-mL flask of Ne at 500 torr is connect

ed to a 300 mL flask of Xe at 700 torr.

If the gases are allowed to mix and fill both

flasks, what will be the partial pressure

of each gas and what will be the

total pressure of the mixture?

Expert Solution

After mixing , number of moles of each gas remains same , temperature is constant .

P1V1 = P2V2

500torr × 500ml = P_Ne ×(500+300)ml

P_Ne = 500×500/800 Torr = 312.5 Torr

Similarly we can apply for Xe gas :

P_Xe = 700torr × 300ml/(300+500)ml = 262.5 Torr

P_total = 312.5 + 262.5 = 575 Torr

Partial pressure of Ne = 312.5torr

Partial pressure of Xe = 262.5torr

Total pressure of mixture = 575torr

queen_honey_blossom answered 2 years ago

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