In: Chemistry
In the laboratory you dissolve 21.5 g of ammonium chloride in a volumetric flask and add water to a total volume of 500 . mL.
weight of NH4Cl = 21.5g
gram molecular weight of NH4Cl = 53.491g/mole
volume of solution = 500ml
molarity = W*1000/G.M.Wt * volume of solution in ml
= 21.5*1000/53.491*500 = 0.804M
NH4Cl(aq) -----------> NH4^+(aq) + Cl^-
0.804M 0.804M 0.804M
concentration of NH4^+ = 0.804M
concentration of Cl^- = 0.804M