Why does the Howard Curren use pure oxygen for the activated sludge process?

Expert Solution

The resulting facilities include the following:

Pre-aeration for hydrogen sulfide stripping and odor control. Hydrogen sulfide levels influent to the odor control system sometimes approach 1200 mg/L.
Step-feed improvements to oxygen activated sludge reactors and conversion of the facilities to the first stage of a two-stage system.
Conversion of aerobic digestion tanks to wastewater reactors using fine bubble diffusers. The converted tanks serve as the nitrification stage following carbonaceous treatment in the first-stage, oxygen system.
New deep-bed denitrification filters.
A major expansion to the plant's maintenance building.
A new 27,000-sf administration building to house laboratories and plant administrative offices.
A standby power facility with four 2000-KW engine generators.
Co-generation facilities featuring five 500-KW engine generators using sludge gas as the fuel.
Digested sludge is dewatered using belt filter presses and converted to biosolids using heat drying.

One of the key design features of the plant is the philosophy of providing flexibility. For example, the oxygen activated sludge system can be operated in parallel or in series with the conventional activated sludge system. Also, denitrification at the filters can be supplemented by denitrification in the activated sludge system. This flexibility allows the operators the tools to adjust to various conditions.

Amanda K answered 2 years ago

1-S0 in an activated sludge process represents _________________________ concentration. 2-X in an activated sludge process represents...

1-S0 in an activated sludge process represents _________________________ concentration. 2-X in an activated sludge process represents ___________________________ concentration. 3-Biomass present in the influent is a product of biomass concentration in the influent multiplied by ______________ ___________. 4-Hydraulic detention time is a ratio of ______________ and _________________. 5- ___________________ represents the portion of microorganisms discharged from the process.

Why aeration is important for activated sludge process? What would be the effect on the DO...

Why aeration is important for activated sludge process? What would be the effect on the DO profile with time (provide a sketch) and BOD removal and sludge production if: Pumping more air than the required amount

A completely mixed activated sludge process is to be used to treat a flow rate of...

A completely mixed activated sludge process is to be used to treat a flow rate of 2.5 MGD. Design a rectangular activated sludge reactor with a 4:1 ratio of length to width. (design only 1 reactor for all flow). The effluent from the plant must not exceed 15 mg/L of BOD5. Use the following design criteria: a. BOD5 influent = 250.0 mg/L b. MLVSS (X) = 3500 mg/L c. Reactor depth = 11 ft d. Effluent BOD5 must be less...

An activated sludge process with an aeration basin volume of 0.3 MG is treating wastewater with...

An activated sludge process with an aeration basin volume of 0.3 MG is treating wastewater with the average daily flow of 2 MGD. The raw sewage entering the treatment plant has an average BOD5 of 400 mg/L. The primary treatment removes 25% of BOD5 and the subsequent activated sludge process is designed to remove 90% of BOD5. Given: Plant effluent BOD5 concentration = 30 mg/L Biomass concentration in the aeration tank = 2,000 mg/L Biomass concentration in the plant effluent...

Two types of flow regime are normally used in the design of an activated sludge process,...

Two types of flow regime are normally used in the design of an activated sludge process, namely completely mixed and plug flow (both are continuous). Using first order kinetic reaction, demonstrate which flow regime provide a better performance, given the followings: Q = 550 m3/d t = 6 hours Co = 225 mg/L k = 0.15 d-1

A wastewater plant with the activated sludge process received 5 × 106 L/day of wastewater with...

A wastewater plant with the activated sludge process received 5 × 106 L/day of wastewater with a BOD5 of 500 mg/L. The primary clarifier removes 30% of the BOD and primary clarify effluent has no biomass (Xi=0 mg/L). Recycle (Qr) and waste sludge (Qw) flows are 25% and 2% of Qin, respectively. Effluent BOD5 from secondary clarifier and waste sludge is 20 mg/L. Microorganism concentration in the waste sludge (Xw) is 6,000 mg/L. Soluble BOD5 is biologically converted into CO2...

9. The following data are given for an activated sludge process: BOD5 (influent) = 250 mg/L...

9. The following data are given for an activated sludge process: BOD5 (influent) = 250 mg/L (soluble) BOD5 (effluent) = 20 mg/L (soluble) MCRT = 10 days MLSS in the aeration tank = 2500 mg/L Concentration of SS in the recycle line = 10,000 mg/L Concentration of SS in the effluent = 30 mg/L (70% biodegradable) BOD5/BODu = 0.75, No nutrient limitations. Yield co-efficient, Y = 0.65 Endogenouse decay coefficient, kd = 0.06/day , Q=5MGD Determine: (a) Find soluble BOD5...

A 100-mL water sample is collected from the activated sludge process of municipal wastewater treatment. The...

A 100-mL water sample is collected from the activated sludge process of municipal wastewater treatment. The sample is placed in a drying dish (weight = 0.5000 g before the sample is added), and then placed in an oven at 104°C until all the moisture is evaporated. The weight of the dried dish is recorded as 0.5625 g. A similar 100-mL sample is filtered and the 100-mL liquid sample that passes through the filter is collected and placed in another drying...

use the general activated sludge /anaerobic digestion model to set up biowin files

what is the rate limiting element in activated sludge design?

Question