Why aeration is important for activated sludge process? What would be the effect on the DO...

Why aeration is important for activated sludge process? What would be the effect on the DO profile with time (provide a sketch) and BOD removal and sludge production if:

Pumping more air than the required amount

Expert Solution

Ally Wells answered 1 year ago

An activated sludge process with an aeration basin volume of 0.3 MG is treating wastewater with...

An activated sludge process with an aeration basin volume of 0.3 MG is treating wastewater with the average daily flow of 2 MGD. The raw sewage entering the treatment plant has an average BOD5 of 400 mg/L. The primary treatment removes 25% of BOD5 and the subsequent activated sludge process is designed to remove 90% of BOD5. Given: Plant effluent BOD5 concentration = 30 mg/L Biomass concentration in the aeration tank = 2,000 mg/L Biomass concentration in the plant effluent...

An activated sludge aeration blower is delivering air to diffusers in an aeration tank. You want...

An activated sludge aeration blower is delivering air to diffusers in an aeration tank. You want to estimate the isentropic efficiency and the work input (by the motor). At the blower inlet, the volumetric flow rate is measured at 85 m3/min, the pressure is 0.98 atm and the temperature is 20⁰C. If the pressure is increased to 1.61 atm and the blower outlet temperature is 350 K: a) what is the blower isentropic efficiency, and b) what is the work...

1-S0 in an activated sludge process represents _________________________ concentration. 2-X in an activated sludge process represents...

1-S0 in an activated sludge process represents _________________________ concentration. 2-X in an activated sludge process represents ___________________________ concentration. 3-Biomass present in the influent is a product of biomass concentration in the influent multiplied by ______________ ___________. 4-Hydraulic detention time is a ratio of ______________ and _________________. 5- ___________________ represents the portion of microorganisms discharged from the process.

Design an aeration tank for activated sludge wastewater treatment designed to meet an effluent standard of...

Design an aeration tank for activated sludge wastewater treatment designed to meet an effluent standard of 10 mg/L BOD5. The flow from the primary effluent is 10 m3/min with a primary effluent BOD5 of 250 mg/L. The design calls for the suspended solids to equal 3500 mg/L for an SRT of 5 days. The decay rate constant is 0.03 day-1 and the yield is 0.75 mg/mg. Determine: the tank volume required to meet these specifications, the resulting mass of sludge...

Design a set of activated sludge aeration tanks. The flow rate to treat is 5.6 MGD...

Design a set of activated sludge aeration tanks. The flow rate to treat is 5.6 MGD and the BOD concentration is 150 mg/L. The design solids concentration (X) at steady-state is 2,000 mg/l. The design MCRT is 7 days. The kinetic coefficients are as follows: K = 2 g BODg cells⋅d, Ks = 25 BOD/L, Kd = 0.06 day-1, Y = 0.5 g BODg cells⋅d. The influent ammonia concentration is 40 mg/l and nitrification is needed. It takes 1400 ft3of...

Data from a field study on a step-aeration activated-sludge secondary are as follows:aeration tank volume =...

Data from a field study on a step-aeration activated-sludge secondary are as follows:aeration tank volume = 120,000 ft3= 0.898 milliongalloninfluent wastewater BOD = 128 mg/Leffluent SS = 26 mg/Leffluent wastewater BOD = 22 mg/Leffluentwastewater flow = 3.67 mgdSS in waste sludge = 11,000 mg/LMLSS in aeration tank = 2350 mg/Lwaste sludge flow = 18,900 gpd = 0.0189 mgd return sludge flow = 1.27 mgd Using these data, calculate BOD loading and MLSS inaeration tank. Also, compute the sludgeage (solids retention...

Why does the Howard Curren use pure oxygen for the activated sludge process?

A completely mixed activated sludge process is to be used to treat a flow rate of...

A completely mixed activated sludge process is to be used to treat a flow rate of 2.5 MGD. Design a rectangular activated sludge reactor with a 4:1 ratio of length to width. (design only 1 reactor for all flow). The effluent from the plant must not exceed 15 mg/L of BOD5. Use the following design criteria: a. BOD5 influent = 250.0 mg/L b. MLVSS (X) = 3500 mg/L c. Reactor depth = 11 ft d. Effluent BOD5 must be less...

what is the rate limiting element in activated sludge design?

What is an activated sludge system and what are the processes that occur in the system?...

What is an activated sludge system and what are the processes that occur in the system? What is the role of "mixed liquor suspended solids"? (hint: draw the system diagram and think about what can be happening)

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