In: Civil Engineering
An activated sludge process with an aeration basin volume of 0.3 MG is treating wastewater with the average daily flow of 2 MGD. The raw sewage entering the treatment plant has an average BOD5 of 400 mg/L. The primary treatment removes 25% of BOD5 and the subsequent activated sludge process is designed to remove 90% of BOD5.
Given:
Plant effluent BOD5 concentration = 30 mg/L
Biomass concentration in the aeration tank = 2,000 mg/L
Biomass concentration in the plant effluent = 20 mg/L
Biomass concentration in the recycle (RAS) = 8,000 mg/L
Flow rate of waste sludge (WAS) = 0.025 MGD
Endogenous decay rate (kd) = 0.01 day-1
a) Calculate the MCRT of the process.
b) Determine the yield coefficient, Y.
c) If µnet, nitrifiers = 0.2/day, would you expect to get nitrification in this system? Briefly describe why or why not and show any supporting calculations.