Question

In: Civil Engineering

A completely mixed activated sludge process is to be used to treat a flow rate of...

A completely mixed activated sludge process is to be used to treat a flow rate of 2.5 MGD. Design a rectangular activated sludge reactor with a 4:1 ratio of length to width. (design only 1 reactor for all flow). The effluent from the plant must not exceed 15 mg/L of BOD5. Use the following design criteria:

a. BOD5 influent = 250.0 mg/L

b. MLVSS (X) = 3500 mg/L

c. Reactor depth = 11 ft

d. Effluent BOD5 must be less than 20 mg/L

e. Y = 0.6 mg VSS/mg BOD5

f. K = 6 day-1

g. KS = 65 mg/L BOD5

h. Kd = 0.08 day -1

i. MLVSS/MLTSS = 0.75

Determine the following: a. Determine the minimum solids retention time (SRT) in days to meet discharge criteria

b. If the actual solids retention time is 4 days, what would be the volume of the activated sludge basin if the wasting flow rate is 40,000 gpd containing 6,400 mg/L of solids.

c. Using the volume of aeration basin in question (b) determine the dimensions of the basin, if the depth is 11 feet, to the nearest even foot

d. What is the hydraulic retention time (HRT) in hours, in the activated sludge basin?

Solutions

Expert Solution


Related Solutions

Design a set of activated sludge aeration tanks. The flow rate to treat is 5.6 MGD...
Design a set of activated sludge aeration tanks. The flow rate to treat is 5.6 MGD and the BOD concentration is 150 mg/L. The design solids concentration (X) at steady-state is 2,000 mg/l. The design MCRT is 7 days. The kinetic coefficients are as follows: K = 2 g BODg cells⋅d, Ks = 25 BOD/L, Kd = 0.06 day-1, Y = 0.5 g BODg cells⋅d. The influent ammonia concentration is 40 mg/l and nitrification is needed. It takes 1400 ft3of...
Two types of flow regime are normally used in the design of an activated sludge process,...
Two types of flow regime are normally used in the design of an activated sludge process, namely completely mixed and plug flow (both are continuous). Using first order kinetic reaction, demonstrate which flow regime provide a better performance, given the followings: Q = 550 m3/d t = 6 hours Co = 225 mg/L k = 0.15 d-1
A completely mixed activated sludge plant is not performing particularly well. You calculate a F:M of...
A completely mixed activated sludge plant is not performing particularly well. You calculate a F:M of 1.5 mg/mg·day-1. What would you recommend to solve the problem? a. Raise the pH b. Increase the dissolved oxygen concentration in the aeration tank c. Lower the pH d. Reduce the amount of sludge wasted
1-S0 in an activated sludge process represents _________________________ concentration. 2-X in an activated sludge process represents...
1-S0 in an activated sludge process represents _________________________ concentration. 2-X in an activated sludge process represents ___________________________ concentration. 3-Biomass present in the influent is a product of biomass concentration in the influent multiplied by ______________ ___________. 4-Hydraulic detention time is a ratio of ______________ and _________________. 5- ___________________ represents the portion of microorganisms discharged from the process.
Primary effluent is to be treated by two parallel trains of the complete mixed activated sludge...
Primary effluent is to be treated by two parallel trains of the complete mixed activated sludge process. Assume average flow conditions, and the primary sedimentation performance is described in question two above. Assume the following for the activated sludge process: i) plant effluent BOD of 8mg/L ii) biomass yield of 0.55kg biomass/kg BOD iii) endogenous decay rate (kd)= 0.04day-1 iv) Solids retention time= 8days v) MLVSS concentration in the aeration tank of 3000mg/L vi) waste and recycle solids concentration of...
what is the rate limiting element in activated sludge design?
what is the rate limiting element in activated sludge design?
The Lolla Hart hospital has a small activated sludge plant to treat its wastewater. The average...
The Lolla Hart hospital has a small activated sludge plant to treat its wastewater. The average daily hospital discharge is 1,500 L per day per bed, and the average soluble BOD5 after primary settling is 500 mg/L. Their permit dictates that the effluent BOD5 and TSS cannot exceed 30 and 20 mg/L, respectively, on an annual basis. Assume the MLVSS concentration in the aeration basin will be maintained at 3,000 mg/L. Also, assume that the concentration of BOD5 of the...
An activated sludge system with recycle (CMFR) uses to treat primary effluent after sedimentation.Use the appropriate...
An activated sludge system with recycle (CMFR) uses to treat primary effluent after sedimentation.Use the appropriate kinetic coefficients for the influent water characteristics to CMFR. Influent Characteristics: Flow = 1000 m3/day; bsCOD= 192 g/m3; nbVSS= 30 g/m3; inert inorganics= 10 g/m3 Aeration Tank Data: MLVSS = 2500; g/m3; SRT or θc = 6-day Calculate: 1.- Fraction of Biomass in MLVSS 2.- Observed yield a) gVSS/ g bs COD b) gTSS/g bs COD 3.- Oxygen Requirement Kg/day
9. What is the importance of controlling the F/M ratio in suspended mixed activated sludge systems?...
9. What is the importance of controlling the F/M ratio in suspended mixed activated sludge systems? What are the implications of a low or high F/M ratio to the settling properties of the biological floc? Please, elaborate your answer.
Assume a biological process can be performed in either a plug flow or completely mixed flow reactor, and the process has a first-order reaction rate K of 0.5 hr-1.
  Assume a biological process can be performed in either a plug flow or completely mixed flow reactor, and the process has a first-order reaction rate K of 0.5 hr-1. Assume an influent concentration of 100 mg/L, a regulatory required effluent concentration of 10 mg/L, and a flow rate of 100 m3/hr. a.   What reactor volume (m3) is required if one completely mixed reactor is used? HINT: use the equation for a first order reaction with a CMR. b.   What...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT