In: Chemistry
Calculate ΔG∘rxn and E∘cell for a redox reaction with n = 3 that has an equilibrium constant of K = 5.3×10−2.
ΔG∘rxn =
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E∘cell = |
We have relation, G 0rxn = - 2.303 R T log K , where K is equilibrium constant.
G 0rxn = - 2.303 8.314 J K -1 mol -1 298 K log 5.3 10 −2
= + 72279 J / mol
= + 7.279 k J / mol
ANSWER : G 0rxn = 7.3 k J / mol
We have relation , G 0 = - n F E 0 cell
Where n = no. of moles of electrons transferred in the overall reaction.
We have, n = 3 , F = 96487 C / mol & G 0 =7.279 k J / mol
72279 J / mol = - 3 96487 C / mol E 0 cell
E 0 cell = 72279 / ( - 3 96487 )
E 0 cell = - 0.2497 V
ANSWER : E 0 cell = - 0.25 V