Question

In: Chemistry

Calculate ΔG∘rxn and E∘cell for a redox reaction with n = 3 that has an equilibrium...

Calculate ΔG∘rxn and E∘cell for a redox reaction with n = 3 that has an equilibrium constant of K = 5.3×10−2.

ΔG∘rxn =

E∘cell =

Solutions

Expert Solution

We have relation, G 0rxn = - 2.303 R T log K , where K is equilibrium constant.

G 0rxn = - 2.303 8.314 J K -1 mol -1 298 K log  5.3 10 −2

= + 72279 J / mol

= + 7.279 k J / mol

ANSWER : G 0rxn = 7.3 k J / mol

We have relation , G 0 = - n F  E 0 cell

Where n = no. of moles of electrons transferred in the overall reaction.

We have, n = 3 , F = 96487 C / mol &   G 0 =7.279 k J / mol

72279 J / mol = - 3 96487 C / mol   E 0 cell  

E 0 cell = 72279 / ( - 3 96487 )

E 0 cell = - 0.2497 V

ANSWER :  E 0 cell = - 0.25 V


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