In: Economics
Project X |
Project Y |
|
Initial cost |
$100,000 |
$150,000 |
Annual operating costs |
30,000 |
20,000 |
Annual repair costs |
10,000 |
6,000 |
Salvage value |
10,000 |
20,000 |
Ans. Cash flows in,
Year 0 = - Initial Cost
=> For X = -$100000 and for Y = -$150000
Year 1-14 = -(Annual Operating cost+ Annual repair cost)
=> For X = -$40000 and for Y = -$26000
Year 15 = -(Annual Operating cost + Annual repair cost) + Salvage value
=> For X = -$30000 and for Y = -$6000
The present worth of X at 10% interest rate,
PWa = -100000 - 40000*(P/A, 10%, 14) - 26000*(P/F, 10%, 15)
=> PWa = -$401849.26
The present worth of Y at 10% interest rate,
PWb = -150000 - 26000*(P/A, 10%, 14) - 6000*(P/F, 10%, 15)
=> PWb = -$342970.23
For EUAW,
PWa = EUAWa * (P/A, 10%, 15)
=> EUAWa = -$52832.64
For EUAW,
PWb = EUAWb*(P/A, 10%, 15)
=> EUAWb = -$45091.59