In: Computer Science
which would evaluate to false? ((x&&!y ||z) || !z&&x)
a. x and y are false
b. x and z are false
c. z is false
d. x y z are true
e. x is false
So only option B is false.
I underlined the high priority in each line so that we have to perform that operation first.
//If you have any doubts comment this answer.