Rank the following in order of increasing polarity: CH3CI, CH3F, and CH3Br

Rank the following in order of increasing polarity: CH₃CI, CH₃F, and CH₃Br

(Please input answers with the following format: CH3CI)

Least polar

Most polar

Expert Solution

Given compounds CH3Cl , CH3F , CH3Br.

If the electronegativity difference of bonded atoms is more, bond polarity is more.

Order of electronegativity of F, Cl, Br is F > Cl > Br

Hence,

electronegativity difference order of bonds is C-F > C-Cl > C-Br

Then,

Bond polarity order is C-F > C-Cl > C-Br

Therefore,

Bond polarity order of given compounds is CH3F > CH3Cl > CH3Br

--------------------------------------

least polar = CH3Br

most polar = CH3F

queen_honey_blossom answered 2 years ago

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