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In: Chemistry

Calculate ? H for the reaction: C4H4(g) + 2 H2(g) — > C4H8(g) ? H =...

Calculate ? H for the reaction: C4H4(g) + 2 H2(g) — > C4H8(g) ? H = ?

Given,

C4H4(g) + 5 O2(g) — > 4 CO2(g) + 2 H2O(l) DH = -2341 kJ

C4H8(g) + 6 O2(g) — > 4 CO2(g) + 4 H2O(l) DH = -2755 kJ

H2(g) + ½ O2(g) — > H2O(l) DH = -286 kJ

Expert Solution

C₄H₄(g) + 2 H₂(g) C₄H₈(g) H = ? -------------- (1)

Given,

C₄H₄(g) + 5 O₂(g) 4 CO₂(g) + 2 H₂O(l) : H₁ = -2341 kJ ------------(2)

C₄H₈(g) + 6 O₂(g) 4 CO₂(g) + 4 H₂O(l) ; H₂ = -2755 kJ ------------(3)

H₂(g) + ½ O₂(g) H₂O(l) ; H₃ = -286 kJ -------------(4)

Eqn (1) can be obtained from the remaining three equations as follows :

Eqn(1) = Eqn(1) + reverse of Eqn(2) + [ 2xEqn(3) ]

So H = H₁ + (- H₂ ) + [ 2x( H₃ )]

= -2341 kJ + (-(-2755 kJ )) + [2x(-286 kJ)]

= -158 kJ

Therefore H for the required equation C₄H₄(g) + 2 H₂(g) C₄H₈(g) is -158 kJ

queen_honey_blossom answered 3 hours ago

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