Question

In: Chemistry

Calculate the ΔH for the reaction. ​2 C (s) + 3 H​2 (g) + 1/2 O​2...

Calculate the ΔH for the reaction.
​2 C (s) + 3 H​2 (g) + 1/2 O​2 (g) = C​2H​5OH (l)
​Given the following information:
​C (s) + O​2 (g) = CO​2 (g)                    ΔH​ = -393.5 KJ/mole
​2 H​2 (g) + O​2 (g) = 2 H​2O (l)                ΔH = -571.6 KJ/mole
​C​2H​5OH (l) + 3 O​2 (g) = 2 CO​2 (g) + 3 H​2O (l)   ΔH​ = -1367.5 KJ/mole

Solutions

Expert Solution

multiply reaction 1 with 2

2C(S)   + 2O2(g)   -------------> 2CO2(g)   H = -787 KJ / mol

multiply reaction 2 with 1.5

3H2(g)   + 1.5O2(g)    ---------------> 3H2O(l) H = -1143.2 KJ/mol

reverse equation 3 and add all

2CO2(g)    + 3H2O(l)    ------------> 3O2(g)   + C2H5OH(l)    H = 1367.5 KJ/mol

3H2(g)   + 1.5O2(g)    ---------------> 3H2O(l) H = -1143.2 KJ/mol

2C(S)   + 2O2(g)   -------------> 2CO2(g)   H = -787 KJ / mol

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2C(C) + 3H2(g)  +1/2O2(g) --------------> C2H2OH(l) H = -562.7 KJ/mol

queen_honey_blossom answered 2 years ago
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