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A small block with mass 0.0400 kg is moving in the xy-plane. The net force on...

A small block with mass 0.0400 kg is moving in the xy-plane. The net force on the block is described by the potential- energy function U(x,y)= (6.00 J/m2 )x2-(3.40 J/m3 )

Part A

What is the magnitude of the acceleration of the block when it is at the point x= 0.31 m , y= 0.61 m ?

Part B

What is the direction of the acceleration of the block when it is at the point x= 0.31 m , y= 0.61 m ?

Solutions

Expert Solution

genius_generous answered 3 hours ago
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