Question
In: Physics
A small block with mass 0.0400 kg slides in a vertical circle of radius 0.500 m...
A small block with mass 0.0400 kg slides in a vertical circle of
radius 0.500 m on the inside of a circular track. During one of the
revolutions of the block, when the block is at the bottom of its
path, point A, the magnitude of the normal force exerted
on the block by the track has magnitude 4N . In this same
revolution, when the block reaches the top of its path, point
B, the magnitude of the normal force exerted on the block
has magnitude 0.660 N .
How much work was done on the block by friction during the motion
of the block from point A to point B?
Solutions
genius_generous answered 2 years agoRelated Solutions
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A small block with mass 0.0550 kg slides in a vertical circle of
radius 0.0740 m on the inside of a circular track. There is no
friction between the track and the block. At the bottom of the
block's path, the normal force the track exerts on the block has
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A small block with mass
0.0475kg
slides in a vertical circle of radius
0.0770m
on the inside of a circular track. There is no
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block's path, the normal force the track exerts on the block has
magnitude 3.90N
Part
A
What is the magnitude of the normal
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In the figure, a small block of mass m = 0.121 kg slides down a frictionless...
In the figure, a small block of mass m = 0.121 kg slides down a
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A small block with mass 0.0400 kg is moving in the xy-plane. The
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A small block with mass 0.0400 kg is moving in the xy-plane. The net force on...
A small block with mass 0.0400 kg is moving in the
xy-plane. The net force on the block is described by the
potential- energy function U(x,y)= (5.90 J/m2 )x2-(3.50 J/m3
)y3.
A)
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Express your answer with the appropriate units.
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After t = 0.32 s what is the speed of the block?
At t = 0.32 s what is the magnitude of the net force on the...
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