Question

In: Chemistry

3. Ethanol can be produced by the fermentation of glucose in the presence of yeast according...

3. Ethanol can be produced by the fermentation of glucose in the presence of yeast according to the following chemical reaction:

C₆H₁₂O₆ -----> 2C₂H₅OH+2CO₂

The feed to the fermenter (not the fresh feed) is 130 mol/s and is 88.1mol% glucose and 11.9 mol% yeast (consider the yeast to be a non-consumable catalyst). The single pass conversion of glucose is 18.6%. The mixed stream exiting the fermenter is passed through a separator that produces a CO₂ stream and an ethanol product stream and a third stream containing the remaining glucose and yeast. 5.67% of the third (glucose/yeast) stream is purged from the process while the rest is recycled to the fermenter feed.

a) Draw the process flow diagram, number the streams, and label the species in each stream.

b) Determine the molar flow rate and composition of the fresh feed.

c) Determine the overall conversion of glucose.

Solutions

Expert Solution

Feed to the reactor = 130 mol/S , Glucose in the feed =130*0.881=114.53 Mol/S

Yeast = 130-114.53=15.47 mol/s

Single pass conversion= 18.6%, glucose converted= 114.53*18.6/100 =21.30 mol/s

Ethanol formed= 2*21.3= 42.6 mol/s and CO2 produced= 42.6 mol/s

Glucose remaining= 114.53-21.30= 93.23 mol/s Yeast= 15.47 mol/s

Total of glucose + yeast=93.23+15.47= 108.70 mol/s

Glucose percentage in the waste= 100*93.23/108.70=85.78%

5.67% of this is purge and rest is recycled, Purged= 108.7*5.67/100 =6.123 mol/s

Recycled = 108.70- 6.123=102.577 mol/s

Glucose in the recycle= 102.577*85.78/100=88 mol/s

Balance is yeast= 102.577- 88= 15.477 mol/s

Feed entering the reactor = Fresh feed + Recycle

Recycle = 102.577 mol/s

130 = Fresh feed + 102.577

Fresh feed= 130-102.577= 27.423 mol/s

Glucose entering the reactor= Glucose in the fresh feed + glucose in the recycle

114.53= 88+ Glucose in the Fresh feed

Glucose in the fresh feed = 114.53-88 =26.53 mol/s

Yeast= Fresh Feed- Glucose in the feed = 27.423- 26.530=0.893 mol/s

26.53 mol/s of glucose upon 100% conversion gives 2*26.53 mol/s of ethanol =53.06 mol/s

Ethanol actually produced= 42.6 mole/s

Percent conversion = 100*42.6/53.06=79.27%

queen_honey_blossom answered 1 year ago

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