In: Physics
The reflecting surfaces of two intersecting flat mirrors are at an angle of 57?, as shown in the figure. A light ray strikes the horizontal mirror at an angle of 57? with respect to the mirror
The given figure can be represented as

In the figure,
57o +
CBD =
90o
CBD =
33o
BD is a normal. From the law of reflection,
ABD =
CBD
= 33o
Now,
66o +
BAF =
90o
BAF =
24o
Again, EF is a normal. From the law of reflection,
BAF =
DAF
= 24o
In triangle ABC,
ABC +
BAC+
ACB =
180o
66o + 48o +
=
180o
=
66o
Therefore,
=
66o.