Solving Differential Equations using Laplace Transform

a) y" - y' -2y = 0

y(0) = 1, y'(0) = 0

answer: y = 1/3e^2t + 2/3e^-t

b) y" + y = sin2t

y(0) = 2, y'(0) = 1

answer: y(t) = 2cost + 5/3 sint - 1/3sin2t

c) y^4 - y = 0

y(0) = 0, y'(0) = 1, y"(0) = 0, y'''(0) = 0

answer y(t) = (sinht + sint)/2

Expert Solution

Colby Messinger answered 2 years ago

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