Question

In: Statistics and Probability

7.) As part of its quality assurance program, the Autolite Battery Company conducted test on battery...

7.) As part of its quality assurance program, the Autolite Battery Company conducted test on battery life. For a particular D-cell alkaline battery, the mean life is 19 hours. The useful life of the battery follows a normal distribution with a standard deviation of 1.2 hours.

a) About 68% of the batteries failed between what two values?

b) About 95% of the batteries failed between what two values?

c) Virtually all of the batteries failed between what two values?

Please show work using Excel.

Solutions

Expert Solution

We have given the normal distribution

Empirical rule

We plug the value of mean and standard deviation

Approximately 68 % batteries will fail between 19 - 1.2 = 17.8 and 19 + 1.2 = 20.2

Answer for a ) part

Approximately 68 % batteries will fail between 17.8 and 20.2 hours

We plug the value of mean and standard deviation

Approximately 95 % batteries will fail between 19 - 2*1.2 = 19 - 2,4 =16.6 and 19 + 2*1.2 = 19 + 2.4= 21.4

Answer for b part

Approximately 95 % batteries will fail between 16.6 and 21.4 hours

We plug the value of mean and standard deviation

Approximately 99.7 % batteries will fail between 19 - 3*1.2 = 19 - 3.6 =15.4 and 19 + 3*1.2 = 19 + 3.6=22.6

Virtually all failed between 15.4 and 22.6 hours

Answer for C part

Virtually all failed between 15.4 and 22.6 hours

Answers :-

a ) Approximately 68 % batteries will fail between 17.8 and 20.2 hours

b ) Approximately 95 % batteries will fail between 16.6 and 21.4 hours

c ) Virtually all failed between 15.4 and 22.6 hours

Look the image of normal distribution

I hope this will help you :)


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