In: Statistics and Probability
Derive below Results 1 to 4 from Axioms 1 to 3.
Axiom 1: P(A)≥ 0
Axiom 2: P(S)=1
Axiom 3: If A and B are mutually exclusive events, then P(A ∪ B)= P(A)+P(B)
Result 1: P(Ac)=1−P(A)
Result 2: For any two events A and B, P (A∪B) = P (A)+P (B)−P (A∩B)
Result 3: For any two events A and B, P(A) = P(A ∩ B) + P(A ∩ Bc)
Result 4: If B ⊂ A, then A ∩ B = B. Therefore, P(A) − P(B) = P(A ∩ Bc), and P(A) ? P(B).