x 0 1 2 3 4 P(X) .45 .3 .2 .04 .01 (c) Find the probability...

x	0	1	2	3	4
P(X)	.45	.3	.2	.04	.01

(c) Find the probability that a person has 1 sibling given that they have less than 3 siblings. Hint: Use the conditional formula: P(A|B)=P(A and B)/P(B). In this case A: event of having 1 sibling and B: event of having less than 3 siblings.

(d) Find the probability that a person has at least 1 sibling OR less than 2 siblings. Hint: Use the General Addition Rule: P(A or B)=P(A)+P(B)-P(A and B). In this case A: event of having at least 1 sibling and B: event of having less than 2 siblings.

Solutions

Expert Solution

x	0	1	2	3	4
p(x)	0.45	0.3	0.2	0.04	0.01

Here,

Now

Therefore, the probability that a person has 1 sibling given that they have less than 3 siblings is 0.4737

Here

And

Now

Therefore, the probability that a person has at least 1 sibling OR less than 2 siblings = 1

orchestra answered 1 year ago

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