In: Statistics and Probability
So, this mean value = 4.095 on our scale. We want to compare the mean value of CONTROL in our survey of St. Louis area respondents to the expected value of 4.095 from the global value survey.
When want to compare the mean value for Control for a global value of 4.095
Test for normality using the Wilcoxon signed-rank test to test the hypotheses:
• Ho: CONTROL = 4.095
• Ha: CONTROL ≠ 4.095
This St. Louis Control value below:
Control |
5 |
6 |
7 |
4 |
5 |
2 |
5 |
4 |
6 |
.
Answer -
Using R software
Here we have to test the hypotheses
Ho: CONTROL = 4.095
Ha: CONTROL ≠ 4.095
Wilcoxon signed-rank test statistics value = 34
and p value = 0.1902
Here p value is greater than 0.05, hence we conclude that we accept null hypothesis at 5% level of significance.
R-Code
R-Output-