Question

In: Statistics and Probability

We want to compare the mean of the hospital stay by sex at this particular Pennsylvania...

We want to compare the mean of the hospital stay by sex at this particular Pennsylvania hospital. Let’s assume that the data are normally distributed and we are assuming that the SD for sexes are equal.    So, is there a difference in the mean hospital stay in Pennsylvania hospital by gender?    (Please include SPSS output here)

State the null and alternative hypotheses.   

What is your test statistics and why?  (no calculation needed)

What were your test statistics results? What is your conclusion?

Id

Dur_stay

Age

Sex

Temp

WBC

Antibio

Bact_cul

Service

1

5

30

2

99

8

2

2

1

2

10

73

2

98

5

2

1

1

3

6

40

2

99

12

2

2

2

4

11

47

2

98.2

4

2

2

2

5

5

25

2

98.5

11

2

2

2

6

14

82

1

96.8

6

1

2

2

7

30

60

1

99.5

8

1

1

1

8

11

56

2

98.6

7

2

2

1

9

17

43

2

98

7

2

2

1

10

3

50

1

98

12

2

1

2

11

9

59

2

97.6

7

2

1

1

12

3

4

1

97.8

3

2

2

2

13

8

22

2

99.5

11

1

2

2

14

8

33

2

98.4

14

1

1

2

15

5

20

2

98.4

11

2

1

2

16

5

32

1

99

9

2

2

2

17

7

36

1

99.2

6

1

2

2

18

4

69

1

98

6

2

2

2

19

3

47

1

97

5

1

2

1

20

7

22

1

98.2

6

2

2

2

21

9

11

1

98.2

10

2

2

2

22

11

19

1

98.6

14

1

2

2

23

11

67

2

97.6

4

2

2

1

24

9

43

2

98.6

5

2

2

2

25

4

41

2

98

5

2

2

1

Please note: the table below might not be needed; however, these are my calculations for Mean and SD for sexes.

Status

n

(sample size)

Mean

(Duration of Days in hospital)

Standard Deviations (s)

Male

11

8.73

7.913

Female

14

8.50

3.481

Solutions

Expert Solution

H0: Null Hypothesis:

HA: Alternative Hypothesis:

where Sample 1 refers to hospital stay by males and Sample 2 refers to hospital stay by females

2 Sample t test

REASON: Population SD is not provided. The Sample Size is small < 30.

Test statistic is:

t = (8.73 - 8.50)/2.3517 = 0.0978

Take =0.05

ndf = n1 + n2 - 2 = 11 + 14 - 2 = 23

From Table, critical values of t = 2.0687

Since the calculated value of t = 0.0978 is less than critical value of t = 2.0687, the difference is not significant. Fail to reject null hypothesis.

Conclusion:

The data do not support the claim that there is a difference in mean hospital stay in Pennsylvania hospital by gender.

So,

Answers to questions asked:
(1)

H0: Null Hypothesis:

HA: Alternative Hypothesis:

where Sample 1 refers to hospital stay by males and Sample 2 refers to hospital stay by females

(2)

2 Sample t test

REASON: Population SD is not provided. The Sample Size is small < 30.

(3)

Test statistic is:

t = 0.0978

Since the calculated value of t = 0.0978 is less than critical value of t = 2.0687, the difference is not significant. Fail to reject null hypothesis.

Conclusion:

The data do not support the claim that there is a difference in mean hospital stay in Pennsylvania hospital by gender.

orchestra answered 1 year ago
Next > < Previous

Related Solutions

A hospital conducted a survey to estimate the mean length of stay at the hospital. a...
A hospital conducted a survey to estimate the mean length of stay at the hospital. a simple random sample of 100 patients resulted in a sample mean of 4.5 days. the population standard deviation is 4 days. a) Calculate a 90% confidence interval. b)Interpret the results of your confidence interval.
So, this mean value = 4.095 on our scale. We want to compare the mean value...
So, this mean value = 4.095 on our scale. We want to compare the mean value of CONTROL in our survey of St. Louis area respondents to the expected value of 4.095 from the global value survey. When want to compare the mean value for Control for a global value of 4.095 Test for normality using the Wilcoxon signed-rank test to test the hypotheses: • Ho: CONTROL = 4.095 • Ha: CONTROL ≠ 4.095 This St. Louis Control value below:...
In a population survey of patients in a rehabilitation hospital, the mean length of stay in...
In a population survey of patients in a rehabilitation hospital, the mean length of stay in the hospital was 12.0 weeks with a standard deviation equal to 1.0 week. The distribution was normally distributed. What is the percentile rank for each of the following z scores? Enter the percentile rank to the right of each z score. Assume a normal distribution. a) 1.23 _____ b) 0.89 ______ c) -0.46 _____ d) -1.00 ______
a hospital administrator wants to estimate the mean length of stay for all inpatients in the...
a hospital administrator wants to estimate the mean length of stay for all inpatients in the hospital. Based on a random sample of 676 patients from the previous year, she finds that the sample mean is 5.3 days with a standard deviation of 1.2 days. Construct and interpret a 95% and a 99% confidence interval for the mean.
24. A hospital would like to determine the mean length of stay for its stroke patients....
24. A hospital would like to determine the mean length of stay for its stroke patients. They observe a random sample of 6 patients, the resulting length of stay of stroke patients are: 6, 7, 5, 8, 11, 2 (in days) Suppose the true length of stay follows normal distribution, a 95% confidence interval for population mean is ____. (4 decimal places) Use the information to answer Q25-27 A 98% confidence interval for the mean number of credit hours that...
We want to examine the relationship between sex offenders and victims of violent crime. In the...
We want to examine the relationship between sex offenders and victims of violent crime. In the following table, U.S. Department of Justice 2011 data for the sex of offenders and the sex of victims are reported. Sex of Offender Sex of Offender Sex of Victim Male Female Male 3760 450 Female 1590 140 1. Treating sex of offender as the independent variable, how many errors of predictions will be made if the independent variable is ignored? 2. How many fewer...
We want to examine the relationship between sex offenders and victims of violent crime. In the...
We want to examine the relationship between sex offenders and victims of violent crime. In the following table, U.S. Department of Justice 2011 data for the sex of offenders and the sex of victims are reported. Sex of Offender Sex of Offender Sex of Victim Male Female Male 3760 450 Female 1590 140 1. Treating sex of offender as the independent variable, how many errors of predictions will be made if the independent variable is ignored? 2. How many fewer...
Using the R built-in data set called Chick Weight, we want to compare the mean weight...
Using the R built-in data set called Chick Weight, we want to compare the mean weight across the different types of Diet. IMPORTANT: We only want to compare chicks at the final value of Time, 21. In this problem, use ?? = 0.05. Make a boxplot to compare weight across the different types of Diet. Based on the boxplot, describe any differences (or lack of differences) you see. Run an ANOVA to compare weight across the different types of Diet....
1. A hospital determined that the average duration of a stay at the hospital is 7.1...
1. A hospital determined that the average duration of a stay at the hospital is 7.1 days. Suppose that the population standard deviation for the duration of stays at this hospital is 1.9 days. Researchers randomly select 26 former patients to include in further research on hospital stays. a) Use the central limit theorem to find the approximate probability that total amount of time these 26 patients spent at the hospital exceeds 156 days? b) What assumptions must you make...
A hospital has determined that the average duration of a stay at the hospital is 9.3...
A hospital has determined that the average duration of a stay at the hospital is 9.3 days. Suppose that the population standard deviation for the duration of stays at this hospital is 2.3 days. Researchers randomly select 36 former patients to include in further research on hospital stays. Use the central limit theorem to find the approximate probability that total amount of time these 36 patients spent at the hospital exceeds 180 days?
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT