In: Statistics and Probability
Nonsmokers |
Smokers |
Quitters |
19 |
26 |
37 |
23 |
29 |
32 |
17 |
22 |
27 |
20 |
30 |
41 |
26 |
23 |
38 |
What are the means for the three groups? Compute the sums of squares, degrees of freedom, and mean squares for these data. What is value of F? Using an alpha of .05, is the F statistically significant? Describe the results of the analyze.
The following table is obtained:
Group 1 | Group 2 | Group 3 | |
19 | 26 | 37 | |
23 | 29 | 32 | |
17 | 22 | 27 | |
20 | 30 | 41 | |
26 | 23 | 38 | |
Sum = | 105 | 130 | 175 |
mean = | 21 | 26 | 35 |
∑iXij2= | 2255 | 3430 | 6247 |
St. Dev. = | 3.536 | 3.536 | 5.523 |
SS = | 50 | 50 | 122 |
n = | 5 | 5 | 5 |
(5) Conclusion
It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to claim that F is statistically significant at the \alpha = 0.05α=0.05 significance level
Finally we get the Anova table as
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 503.3333 | 2 | 251.6667 | 13.6036 | 0.000822 | 3.885294 |
Within Groups | 222 | 12 | 18.5 | |||
Total | 725.3333 | 14 |