For the following sequence read that comes from an internal exon within a gene, what is...

For the following sequence read that comes from an internal exon within a gene, what is the amino acid sequence that is encoded?

5’ TTAAGTAGCCGCTAG 3’

Expert Solution

The given sequence of the DNA is

5’ TTAAGTAGCCGCTAG 3’

Since it is in 5' to 3' direction, it is the coding strand of the DNA.

the template strand of the DNA will be complementary to the coding strand of the DNA.

The sequence of the template strand DNA: 3' AATTCATCGGCGATC 5'

Now, the mRNA will be synthesised by the process of transcription in which template DNA will act as a template for the mRNA synthesis. The mRNA will be complementary to the template strand of the DNA.

so, the sequence of mRNA will be: 5' UUA AGU AGC CGC UAG 3'

The translation is the process in which the polypeptide chain is synthesized with mRNA as a template. The tRNA and ribosomes assist this process. The mRNA consists of the nitrogenous base sequence which acts as the template. A codon is a three-base group in the mRNA which is used in the translation process. These codons are used as a recognition site for the anticodons to bind to them and the tRNA (where the anticodons are already located on the other side) release the one corresponding amino acid (located on that tRNA molecule) to the growing polypeptide chain. This process goes on and a polypeptide chain is produced.

So, the amino acid sequence will be: LEU SER SER ARG STOP (leucine serine serine arginine stop)

or in one-letter code, the amino acid sequence is: L S S R STOP

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gladiator answered 2 years ago

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