In: Statistics and Probability
Predict the 2007 cost of living index of city 2 and find its residual. The predicted 2007 cost of living index of city 2 is nothing . (Round to one decimal place as needed.)
| City | Index_2006 | Index_2007 |
| 1 | 117.3 | 125.7 |
| 2 | 121.8 | 122 |
| 3 | 102.3 | 104.3 |
| 4 | 93 | 95.8 |
| 5 | 111.7 | 119.6 |
| 6 | 112.9 | 124.8 |
| 7 | 95.3 | 97.3 |
| 8 | 109.9 | 111.5 |
| 9 | 100.5 | 101.8 |
| 10 | 95.8 | 103.6 |
| 11 | 121.2 | 121.4 |
| 12 | 119.3 | 124.6 |
| 13 | 105.9 | 118.3 |
| 14 | 111.2 | 119.4 |
| 15 | 111.3 | 115.8 |
Solution: We can use the excel regression data analysis tool to find the least-squares regression equation. The excel output is given below:
| SUMMARY OUTPUT | ||||||
| Regression Statistics | ||||||
| Multiple R | 0.92034249 | |||||
| R Square | 0.8470303 | |||||
| Adjusted R Square | 0.8352634 | |||||
| Standard Error | 4.247539479 | |||||
| Observations | 15 | |||||
| ANOVA | ||||||
| df | SS | MS | F | Significance F | ||
| Regression | 1 | 1298.708642 | 1298.708642 | 71.98415025 | 0.0000 | |
| Residual | 13 | 234.5406911 | 18.04159162 | |||
| Total | 14 | 1533.249333 | ||||
| Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | |
| Intercept | 3.6052 | 13.0256 | 0.2768 | 0.7863 | -24.5350 | 31.7453 |
| Index_2006 | 1.0138 | 0.1195 | 8.4843 | 0.0000 | 0.7556 | 1.2719 |
Therefore, the regression equation is:

Therefore, the predicted 2007 cost of living index of city 2 is


Therefore, the residual is:
