Question

In: Statistics and Probability

Develop a simple linear regression model to predict the Cost of Living Index based upon Restaurant...

Develop a simple linear regression model to predict the Cost of Living Index based upon Restaurant Price Index using a 95% level of confidence.

  1. Write the reqression equation.
  2. Discuss the statistical significance of the model as a whole using the appropriate regression statistic at a 95% level of confidence.
  3. Discuss the statistical significance of the coefficient for the independent variable using the appropriate regression statistic at a 95% level of confidence.
  4. Interpret the coefficient for the independent variable.
  5. What percentage of the observed variation in income is explained by the model?
  6. Predict the value of the cost of living index using this regression model with a Restaurant Price Index of 110.00

Create a table and compare the preceding three simple linear regression models to determine which model is the preferred model. Use the Significance F values, p-values for independent variable coefficients, R-squared or Adjusted R-squared values (as appropriate), and standard errors to explain your selection.

Data from Excel File

City

Cost of Living Index

Rent Index

Groceries Index

Restaurant Price Index

Local Purchasing Power Index

Luanda, Angola

150.82

138.03

171.77

121.3

50.27

Basel, Switzerland

145.92

62.61

139.31

134.41

144.12

Lausanne, Switzerland

140.88

57.61

144.89

117.3

165.05

Perth, Australia

138.97

72.08

126.03

131.02

112.02

Bern, Switzerland

136.3

57.31

133.11

124.59

158

Sydney, Australia

135.92

93.61

125.27

113.28

116.18

Solutions

Expert Solution

a)

Using Excel

data -> data analysis -> regression

SUMMARY OUTPUT
Regression Statistics
Multiple R 0.271149
R Square 0.073522
Adjusted R Square -0.1581
Standard Error 6.299925
Observations 6
ANOVA
df SS MS F Significance F
Regression 1 12.59825 12.59825 0.317424 0.603245
Residual 4 158.7562 39.68906
Total 5 171.3545
Coefficients Standard Error t Stat P-value Lower 95% Upper 95%
Intercept 117.0995 43.32936 2.702543 0.053952 -3.20214 237.4011
Restaurant Price Index 0.197079 0.349802 0.563404 0.603245 -0.77413 1.168284

y^ = 117.0995 + 0.1971 x

b)

F = 0.3174

p-value = 0.6032

since p-value > alpha

we fail to reject the null hypothesis

the model is not significant

c)

p-value of independent variable is also same 0.6032

since p-value > alpha

we fail to reject the null hypothesis

we conclude that the independent variable is not significant

d)

when restaurant price index increase by 1, on average cost of living index increase by 0.1971

e)

R^2 = 0.0735

hence 7.35 %

f)

x = 110

y^ = 117.0995 + 0.1971 *110

= 138.7805


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