How much heat, in kJ, is absorbed by a 77.0 g sample of aluminum at 25.0°C...

How much heat, in kJ, is absorbed by a 77.0 g sample of aluminum at 25.0°C when it is immersed in boiling water? The specific heat capacity of aluminum is 0.900 J/g°C and the specific heat capacity of water is 4.184 J/g°C. Enter your answer with no units.

Need some help on this one. Please show work/relevant formulas. Thanks for any help!

Expert Solution

Heat absorbed by aluminium, Q = mcdt

Where

m = mass of aluminium = 77.0 g

c = specific heat capacity of aluminum = 0.900 J/g°C

dt = change in temperature of aluminium = final temperature - initial temperature

= 100 - 25

= 75 ^oC

Plug the values we get Q = mcdt

= 77.0x0.900x75 J

= 5.2 x10³ J

= 5.2 kJ Since 1kJ = 10³ J

Therefore the heat absorbed is 5.2 kJ

queen_honey_blossom answered 1 month ago

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