Question

In: Chemistry

how much heat (in kj) is needed to convert 866 g of ice at -10 c...

how much heat (in kj) is needed to convert 866 g of ice at -10 c to steam at 126 c?

spH of ice and steam are 2.03J/g*c and 1.99J/g*c, respectively.

Solutions

Expert Solution


See, the total energy needed for this conversion is the sum of the energy to heat the -10 °C ice to 0 °C ice, melting the 0 °C ice into 0 °C water, heating the water to 100 °C, converting 100 °C water to 100 °C steam and heating the steam to 126 °C(this is because of phase transitions that take place while converting from ice to steam.)

we will do in different steps.

1) Heat required to raise the temperature of ice from -10 °C to 0 °C

we will use the formula:
q = mcΔT

where
q = heat energy
m = mass
c = specific heat
ΔT = change in temperature

q = (866 g)x(2.03 J/g·°C)[(0 °C - (-10 °C)]
q = (866 g)x(2.03 J/g·°C)x(10 °C)
q = 17579.8 J

Heat required to raise the temperature of ice from -10 °C to 0 °C = 17579.7 J = 17.5798 kJ

2) Heat required to convert 0 °C ice to 0 °C water

Using the formula

q = m·ΔHf

where
q = heat energy
m = mass
ΔHf = heat of fusion

q = (866 g)x(334 J/g) (heat of fusion taken from google)
q = 289244 J = 289.244 kJ

Heat required to convert 0 °C ice to 0 °C water = 289.244 kJ

3) Heat required to raise the temperature of 0 °C water to 100 °C water

q = mcΔT

q = (866 g)x(4.18 J/g·°C)[(100 °C - 0 °C)]
q = (866 g)x(4.18 J/g·°C)x(100 °C)
q = 361988 J

Heat required to raise the temperature of 0 °C water to 100 °C water = 361988 J= 361.988 kJ

4) Heat required to convert 100 °C water to 100 °C steam

q = m·ΔHv

where
q = heat energy
m = mass
ΔHv = heat of vaporization

q = (866 g)x(2257 J/g)
q = 1954562 J

Heat required to convert 100 °C water to 100 °C steam = 1954.562 kJ

Step 5: Heat required to convert 100 °C steam to 126 °C steam

q = mcΔT
q = (866 g)x(1.99 J/g·°C)[(126 °C - 100 °C)]
q = (866 g)x(1.99 J/g·°C)x( 26°C)
q = 44806.84 J

Heat required to convert 100 °C steam to 126 °C steam = 44.80684 kJ

Step 6: Find total heat energy

HeatTotal = HeatStep 1 + HeatStep 2 + HeatStep 3 + HeatStep 4 + HeatStep 5
HeatTotal = 2668180.54 J = 2668.18054 kJ


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