Question

Write a program in C++ to display the following patterns:

*

**

***

****

1

12

123

1234

1

22

333

4444

1

2 3

4 5 6

7 8 9 10

1

2 3

4 5 6

7 8 9 10

*

***

*****

*******

*********

*******

*****

***

*

Answer 1

Typed Code:

#include <iostream>

using namespace std;

int main()
{
int i = 0 , j =0;
for(int i = 0;i<4;i++){
for(int j = 0;j<=i;j++){ //Logic to print stars
cout<<"*";
}
cout<<"\n";//after every j loop we need new line
}
cout<<"///SECOND PATTERN//\n";
for(int i = 1;i<=4;i++){
for(int j = 1;j<=i;j++){ //in this logic we are printing j ,with i starting from 1 to 4
cout<<j;
}
cout<<"\n";//after every j loop we need new line
}
cout<<"///THIRD PATTERN//\n";
for(int i = 1;i<=4;i++){ //in this logic we are printing i, with i starting from 1 to 4
for(int j = 1;j<=i;j++){
cout<<i;
}
cout<<"\n";//after every j loop we need new line
}
cout<<"///FOURTH PATTERN//\n";
int k = 1;
for(int i = 1;i<=4;i++){
for(int j = 1;j<=i;j++){//in this logic we are printing a number from 1 with incrementing
//, with i starting from 1 to 4
cout<<k++<<" ";
}
cout<<"\n";//after every j loop we need new line
}
cout<<"///FIFTH PATTERN//\n";
for(int i = 1,k = 1;i<=4;i++){//in this logic we are printing a number from 1 with incrementing
//, with i starting from 1 to 4
for(int j = 1;j<=i;j++){
cout<<k++<<" ";
}
cout<<"\n";//after every j loop we need new line
}
cout<<"///SIXTH PATTERN//\n";
int n = 5;
int m = 2*n; // doubling the number bcz we need to iterate 2*n -1 times
for(int i = 0;i<m;i++){
int x = m/2; //taking half of the number
if(i < x) { //from 1 to less than half of number , it is in inceasing order
for(int j = 0;j<(2*i + 1);j++){ //here 2i +1 gives odd number of stars
cout<<"*";
}
} else { // after half of number we need to print decreasing order
int z = (2*n - (2*i -6)); //logic to print odd number of stars
for(int j = z ;j>=0;j--){ //printing stars with decreasing order
cout<<"*";
}
}

cout<<"\n"; //after every j loop we need new line
}
return 0;
}
SCREEN SHOT :

OUTPUT: