In: Statistics and Probability
I have been getting many incorrect answers recently, if you are unsure please do not attempt. All i ask is all parts answered and with shown or explained work. Thank you (:
The following data represent the math SAT scores for a random sample of seniors from three different high schools.
School A |
School B |
School C |
---|---|---|
488 |
445 |
618 |
592 |
370 |
525 |
537 |
382 |
651 |
470 |
423 |
647 |
539 |
523 |
543 |
Using α=0.05, perform a hypothesis test to determine if the math median SAT score differs among these three high schools.
Here we need to test "wether the math median SAT score differs among these three high schools"
Let's write null hypothesis ( H0 ) and the alternative hypothesis( Ha )
Ha : At least one pair of means of two high schools is different.
Using excel :
step 1) First enter the data in excel column.
step 2) Click on Data >>>Data Analysis>>>Anova: Single Factor
Then click on OK
step 3) select all the data values in "Input range"
Here level of significance is given as 0.05, so Alpha : 0.05
then click on Output Range
Select any empty cell
Look the following image:
then click on OK so we get the following output
p-value = 0.0017
and F critical value =4.885294
Decision rule:
1) If p-value < level of significance (alpha) then we reject null hypothesis
2) If p-value > level of significance (alpha) then we fail to reject null hypothesis.
Here p value = 0.00177 < 0.05 so we used first rule.
That is we reject the null hypothesis
Conclusion: At 5% level of significance there are sufficient differences of at least one pair among the three high schools means.
So correct option is B