In: Operations Management
Demand for oil changes at Garcia's Garage has been as follows:
Month |
Number of Oil Changes |
January |
33 |
February |
53 |
March |
56 |
April |
58 |
May |
69 |
June |
46 |
July |
62 |
August |
69 |
a. Use simple linear regression analysis to develop a forecasting model for monthly demand. In this application, the dependent variable, Y, is monthly demand and the independent variable, X, is the month. For January, let X=1; for February, let X=2; and so on.
The forecasting model is given by the equation Y =4 0.86 +3.31X.
(Enter your responses rounded to two decimal places.)
b. Use the model to forecast demand for September, October, and November. Here,
X=9, 10, and 11, respectively. (Enter your responses rounded to two decimal places.)
Month |
Forecast for the number of Oil Changes |
September |
|
October |
|
November |
PERIOD (X) |
DEMAND (Y) |
X |
Y |
X * Y |
X^2 |
1 |
33 |
1 |
33 |
33 |
1 |
2 |
53 |
2 |
53 |
106 |
4 |
3 |
56 |
3 |
56 |
168 |
9 |
4 |
58 |
4 |
58 |
232 |
16 |
5 |
69 |
5 |
69 |
345 |
25 |
6 |
46 |
6 |
46 |
276 |
36 |
7 |
62 |
7 |
62 |
434 |
49 |
8 |
69 |
8 |
69 |
552 |
64 |
SIGMA |
36 |
446 |
2146 |
204 |
INTERCEPT = (SIGMA(Y) * SIGMA(X^2) - SIGMA(X) * SIGMA(XY)) / (N * SIGMA(X^2) - SIGMA(X)^2)
INTERCEPT = (446 * 204) - (36 * 2146) / ((8 * 204) - 36^2) = 40.86
SLOPE = ((N * SIGMA(XY)) - (SIGMA(X) * SIGMA(Y))) - (N * SIGMA(X^2) - SIGMA(X)^2)
SLOPE = ((8 * 2146) - (36 * 446) / ((8 * 204) - 36^2) = 3.31
Y = A + B(x), WHERE A IS THE INTERCEPT, B IS THE SLOPE, x IS THE PERIOD = 40.86 + (3.31 * X)
FOR THE VALUE OF X = 9 FORECAST = 40.86 + (3.31 * 9) = 70.65
FOR THE VALUE OF X = 10 FORECAST = 40.86 + (3.31 * 10) = 73.96
FOR THE VALUE OF X = 11 FORECAST = 40.86 + (3.31 * 11) = 77.27
** Leaving a thumbs-up would really help me out. Let me know if you face any problems.