In: Statistics and Probability
The demand (in number of copies per day) for a city newspaper,
x, has historically been 43,000, 62,000, 74,000, 89,000, or 104,000
with the respective probabilities .2, .16, .4, .2, and
.04. |
(b) | Find the expected demand. (Round your answer to the nearest whole number.) |
µx |
(c) |
Using Chebyshev's Theorem, find the minimum percentage of all possible daily demand values that will fall in the interval [μx ± 2σx]. (Round your answer to the nearest whole number. Input your answers to minimum percentage and percentage of all possible as percents without percent sign.) |
The minimum percentage of all possible daily demand values is percent. |
(d) |
Calculate the interval [μx ± 2σx]. According to the probability distribution of demand x previously given, what percentage of all possible daily demand values fall in the interval [μx ± 2σx]? (Round your intermediate values to the nearest whole number. Round your answers to the nearest whole number. Input your answers to minimum percentage and percentage of all possible as percents without percent sign.) |
The interval is [ , ]. | ||
The percentage of all possible daily demand values that fall in the interval is percent. |